A golf ball was struck at an angle of 40 degrees with a horizontal displacement of 300 meters. What is the initial velocity?
R= V0 ^2 × Sin(2thetha) / g
Given angle is 40 degrees
And distance 300 metres .
300 = V0^2 x Sin(2thetha) / 2g
300 = V0^2 × Sin(2×40) / (2×9.81)
V0^2 = 5976.80
V0 = SQRT 5976.80
V0=77.30 metres/sec .
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?