What represents the zeros of the function g(x) = x ^{3} - 9x ^{2} + 2x + 48?

g(x) = x^3 - 9x^2 + 2x + 48

Put x = 0 we get

= (0)^3 - 9(0)^2 + 2(0) + 48

= 48

Hence g(0) = 48

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