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What represents the zeros of the function g(x) = x 3 - 9x 2 + 2x + 48?
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Testing for Correlation and Bivariate Regression
Testing for Correlation and Bivariate RegressionYou had the chance earlier in the week to practice with the correlation an ...
Testing for Correlation and Bivariate Regression
Testing for Correlation and Bivariate RegressionYou had the chance earlier in the week to practice with the correlation and simple linear regression and obtain peer feedback. Hopefully you are excited about the potential these tests hold; equally important is that you recognize some of their weaknesses. Now, it is once again time to put all of that good brainstorming to use and answer a social research question with the correlation and simple linear regression. As you begin the Assignment, be sure and pay close attention to the assumptions of the test. Specifically, make sure that your variables are metric level variables that can easily be interpreted in these tests.For this Assignment, you will examine correlation and bivariate regression testing.To prepare for this Assignment:Review this week’s Learning Resources and media program related to regression and correlation.Using the SPSS software, open the Afrobarometer dataset or the High School Longitudinal Study dataset (whichever you choose) found in the Learning Resources for this week.Based on the dataset you chose, construct a research question that can be answered with a Pearson correlation and bivariate regression.Once you perform your correlation and bivariate regression analysis, review Chapter 11 of the Wagner text to understand how to copy and paste your output into your Word document.For this Assignment:Write a 2- to 3-paragraph analysis of your correlation and bivariate regression results for each research question. In your analysis, display the data for the output. Based on your results, provide an explanation of what the implications of social change might be.Use proper APA format, citations, and referencing for your analysis, research question, and display of output.
BUSN 311 American InterContinental Hypothesis Testing & Variance Research Paper
The below scenario describes a real-world or business application that utilizes statistical analysis to help resolve a bu ...
BUSN 311 American InterContinental Hypothesis Testing & Variance Research Paper
The below scenario describes a real-world or business application that utilizes statistical analysis to help resolve a business problem: increasing efficiency by decreasing processing time. Prepare an analysis by completing five steps of the hypothesis testing with one sample. The report should be a minimum of 5 pages in length.
Last week, your manager asked you to analyze staffing needs for the Foreclosure Department. She was so impressed, and she wants you to create another report for her. Her intention is to decrease the processing time per document.
Based on last week's report, the average number of processed documents per hour was 15.11, with a standard deviation of 2.666. That is, one document was reviewed in 238.25 seconds. To be objective as much as possible, the manager spoke with an employee whose average was exactly 15 documents per hour. The employee claimed that if she was given a larger monitor, the processing time would be shorter.
They conducted an experiment with a large monitor and measured processing time. After reviewing 20 documents, the calculated average processing time per document was 190.58 seconds. The manager believes that a bigger monitor helped reduce the processing time for reviewing foreclosure documents. Conduct a hypothesis test using a 95% confidence level, which means that significance level a = 0.05.
Use the 5-step process, and explain each term or concept mentioned in each section in the following.
Step 1: Set Up Null and Alternative Hypotheses
Based on the request description, explain if a one-tailed or two-tailed test is needed. If a one-tailed test is needed, is it a left or right-tailed test? Please explain why one alternative is better than the other.
State both of the following hypotheses:
Null hypothesis
Alternative hypothesis
You will need the following information to progress to Step 2:
Standard deviation: Explain what standard deviation is. Locate the calculated standard deviation in the assignment description, and enter here.
Random variable: Explain what a random variable is. Locate it in the assignment description, and enter here.
Test type: Compare and contrast t-test and z-test. Once done, determine which one is appropriate for the experiment given the fact that the sample size is less than 30.
Step 2: Decide the Level of Significance
Explain what the significance level is, and determine whether the one used in the assignment description is high, medium, or low. What does this significance level tell you about this test? Locate the level of significance in the given scenario, and list it in this step.
Significance level = ?
Determine the degree of freedom based on the number of reviewed documents in the new experiment (n = 20) and based on the formula Degree of freedom = n – 1.
Degree of freedom = ?
Critical value = (You will need to use the t-table and find the intersection point between the degree of freedom and the alpha value that is provided in the assignment description.)
Step 3: Calculate the Test Statistics
Calculate the test statistics based on the test type determined in Step 1.
If the determination was done correctly, you should use this formula to calculate the test statistics.
Test statistics = ?
Step 4: Compare the Calculated Test Statistics and the Critical Value
Construct a bell-shaped diagram showing the critical value and the calculated test statistic.
Step 5: Reach a Conclusion
Was the manager's conclusion correct? Share your conclusions on the assumptions in the scenario using the hypothesis testing that you conducted in the previous four steps.
Business Research Project
Is there a relationship between the sales of a product and the longevity of the product’s display with the type of mater ...
Business Research Project
Is there a relationship between the sales of a product and the longevity of the product’s display with the type of material used and time period of the display?
Statistics Exam 30 questions
1. Say you've obtained a chi-square of 12.56. You have a chi square critical value of 3.481. Based on this information ...
Statistics Exam 30 questions
1. Say you've obtained a chi-square of 12.56. You have a chi square critical value of 3.481. Based on this information, what do you conclude?A) Fail to reject the null hypothesis B) Reject the Null Hypothesis 2. Say you’ve obtained a chi-square of 10.95. You have a chi square critical value of 9.210. Based on this information, what do you conclude?A) Fail to reject the null hypothesis B) Reject the Null Hypothesis 3. For the table below, what would be the chi-square critical value if you were doing a hypothesis test and your significance level was 0.01? Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 A 3.841 B 6.635 C 5.991 D 9.210 4) For the table below, what is the expected frequency for Yes Demoted and Pretty Happy? (Remember that you don't need to do all the expected frequencies to get just one…) General Happiness Total Very Happy Pretty Happy Not Too Happy Were Demoted? Yes 5 12 7 24 No 294 545 99 938 Total 299 557 106 962 7 14 3 543 5. For the table below, what is the expected frequency for No Kids and Yes Counseling for Mental Problems? (Remember that you don’t need to do all the expected frequencies to get just one…) Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 42 16 692 259 6. For the table below, what is the expected frequency for No Demoted and Not too Happy? (Remember that you don't need to do all the expected frequencies to get just one…) General Happiness Total Very Happy Pretty Happy Not Too Happy Were Demoted? Yes 5 12 7 24 No 294 545 99 938 Total 299 557 106 962 7 292 103 543 7. For the table below, what is the expected frequency for No Kids and No Counseling for Mental Problems? (Remember that you don’t need to do all the expected frequencies to get just one…) Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 42 16 692 259 8. In the table below, what is the column marginal for “ever had home broken into = no”? Ever had home broken into? Gender Yes No Total Female 1558 1064 2622 Male 1567 1069 2636 Total 3125 2133 5258 3125 2133 2622 2636 9. For the table below, what is the chi-square? (Remember, you can round to whole numbers for the expected frequency, but leave at least 2 decimal places on for all other chi-square calculations). Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 0.04 0.94 0.36 0.82 10. For the table below, what is the chi-square? (Round this way or the answer will not turn out right: you can round to whole numbers for the expected frequency, but leave at least 2 decimal places on for all other chi-square calculations). Choose the answer that is closest. General Happiness Total Very Happy Pretty Happy Not Too Happy Were Demoted? Yes 5 12 7 24 No 294 545 99 938 Total 299 557 106 962 6.92 2.69 5.96 4.85 11. You've obtained a chi square of 34.56, and it's significant. You want to test how strong the relationship between these two variables is. You have a sample size of 75. You have a table with 2 rows and 4 columns. What's your Cramer's V? 0.46 0.68 0.26 0.53 12. Say you have a phi-coefficient of 0.51. How strong is the relationship between the two variables it tests? Weak Relationship Moderate Relationship Strong Relationship 13. You’ve obtained a chi square of 10.98, and it’s significant. You want to test how strong the relationship between these two variables is. You have a sample size of 50. What’s your phi-coefficient? 0.47 0.56 0.22 0.25 14. You’ve obtained a chi square of 16.52, and it’s significant. You want to test how strong the relationship between these two variables is. You have a sample size of 75. What’s your phi-coefficient? 0.47 0.22 0.69 0.18 15. Is the interpretation of the following regression line correct?Regression line: y ⏜ = 20.5 + 1.4 ( x ) Interpretation: For every one unit increase in y, there is a 1.4 increase in x. True False 16. Is the interpretation of the following regression line correct?Regression line: y ⏜ = 0.89 + 2.3 ( x ) Interpretation: For every one unit increase in y, there is a 0.89 increase in x. True False 17. Is the interpretation of the following regression line correct?Regression line: y ⏜ = 0.5 − 1.7 ( x ) " style="max-width: 694px;" rel="max-width: 694px;"> y ⏜ = 0.5 − 1.7 ( x ) Interpretation: For every one unit increase in x, there is a 1.7 decrease in y. True False 18. What type of relationship, positive or negative, is portrayed in the following sentence? When crime worsens, individuals' willingness to help their neighborhoods decreases. Positive Negative 19. What type of relationship, positive or negative, is portrayed in the following sentence? The statistical relationship shows that when foreclosure rates increase, crime worsens. Positive Negative 20. Find the correlation between the two following variables: % of people in neighborhood on welfare and the number of people who have police contact. x y 40 9 59 25 20 3 15 10 0.832 0.895 0.790 0.867 21. What is the strength of the following correlation? 0.156 Weak Moderate Strong 22. What is the strength of the following correlation? 0.451 Weak Moderate Strong 23. A friend of yours suggests that at least 10% of people at your university have had something stolen from them on campus in the past year. This is your population value. You take a random sample of 100 people in you classes to determine if your friend is correct, you think that they may be wrong. You find that 15% of them have had something stolen. Would you use z or t to test this hypothesis? Z Distribution T Distribution 24. A friend of yours suggests that at least 10% of people at your university have had something stolen from them on campus in the past year. This is your population value. You take a random sample of 100 people in you classes to determine if your friend is correct, you think that they may be wrong. You find that 15% of them have had something stolen. Would you have a one or two tailed test? One tailed Two Tailed 25. A friend of yours suggests that at least 10% of people at your university have had something stolen from them on campus in the past year. This is your population value. You take a random sample of 100 people in you classes to determine if your friend is correct. You find that 15% of them have had something stolen. What is the value of your test statistic? 1.667 2.112 1.521 1.231 26. What are the age differences among teens that report being delinquent (or not)? Conduct a two mean hypothesis test to ascertain whether there is an age difference between teens who report being delinquent and teens that report no delinquency. Use a significance level of α = 0.05 and the information below. No Delinquency Delinquent n = 21 n = 5 s1 = 0.6 s2 = 1.6 x1 = 13 x2 = 17 Would the alternative hypothesis for this test be directional or non-directional? Directional, greater than Directional, less than Non-Directional 27. Let’s say we believe that desk-officers and patrol-officers spend different get differing numbers of overtime hours because of their different assignments. We take a small sample of each group to determine if they are truly different. Conduct a two mean hypothesis test to ascertain whether there is a difference between desk-officers and patrol-officers regarding overtime. Use a significance level of α = 0.01 and the information below. Desk Officers Patrol Officers n = 4 n = 7 s1 = 2.9 s2 = 2.0 x ¯ 1 = 3 x ¯ 2 = 5 What do you conclude? Reject H0 Fail to Reject H0 28. Let’s say we believe that desk-officers and patrol-officers spend different get differing numbers of overtime hours because of their different assignments. We take a small sample of each group to determine if they are truly different. Conduct a two mean hypothesis test to ascertain whether there is a difference between desk-officers and patrol-officers regarding overtime. Use a significance level of α = 0.01 and the information below. Desk Officers Patrol Officers n = 4 n = 7 s1 = 2.9 s2 = 2.0 What is your critical value(s) for this test? ± 2.056 ± 2.365 ± 3.250 ± 2.831 29. Let’s say we believe that desk-officers and patrol-officers spend different get differing numbers of overtime hours because of their different assignments. We take a small sample of each group to determine if they are truly different. Conduct a two mean hypothesis test to ascertain whether there is a difference between desk-officers and patrol-officers regarding overtime. Use a significance level of α = 0.01 and the information below. Desk Officers Patrol Officers n = 4 n = 7 s1 = 2.9 s2 = 2.0 What is the degrees of freedom for this test? 9 11 8 6 30. What are the age differences among teens that report being delinquent (or not)? Conduct a two mean hypothesis test to ascertain whether there is an age difference between teens who report being delinquent and teens that report no delinquency. Use a significance level of α = 0.05 and the information below. No Delinquency Delinquent n = 21 n = 5 s1 = 0.6 s2 = 1.6 What is your obtained t? - 10.211 8.722 -9.430 -16.11
Drink-At-Home, Inc., Statistic and Probability homework help
Drink-At-Home, Inc.
Drink-At-Home, Inc. (DAH, Inc.), develops, processes, and markets
mixes to be used in nonalcoholi ...
Drink-At-Home, Inc., Statistic and Probability homework help
Drink-At-Home, Inc.
Drink-At-Home, Inc. (DAH, Inc.), develops, processes, and markets
mixes to be used in nonalcoholic cocktails and mixed drinks for home
consumption. Mrs. Lee, who is in charge of research and development at DAH,
Inc., this morning notified Mr. Dick Jones, the president, that exciting
developments in the research and development section indicate that a new
beverage, an instant pina colada, should be possible because of a new way to
process and preserve coconut. Mrs. Lee is recommending a major program to develop
the pina colada. She estimates that expenditure on the development may be as
much as $100,000 and that as much as a year's work may be required. In the
discussion with Mr. Jones, she indicated that she thought the possibility of
her outstanding people successfully developing such a drink now that she'd done
all the really important work was in the neighborhood of 90 percent. She also
felt that the likelihood of a competing company developing a similar product in
12 months was 80 percent.
Mr. Jones is strictly a bottom line guy and is concerned about the
sales volume of such a beverage. Consequently, Mr. Jones talked to Mr.
Besnette, his market research manager, whose specialty is new product
evaluation, and was advised that a market existed for an instant pina colada,
but was some-what dependent on acceptance by both grocery stores and retail
liquor stores. Mr. Besnette also indicated that the sales reports indicate that
other firms are considering a line of tropical drinks. If other firms should
develop a competing beverage the market would, of course, be split among them.
Mr. Jones pressed Mr. Besnette to make future sales estimates for various
possibilities and to indicate the present (discounted value of future profits)
value. Mr. Besnette provided Table 1.
Mr. Besnette's figures did not include (1) cost of research and
development, (2) cost of new production equipment, or (3) cost of introducing
the pina colada. The cost of the new production equipment is expected to be $
100,000 because of the special way the coconut needs to be handled, and the
cost of introducing the new product is expected to be about $150,000 because of
the point-of purchase displays that would be necessary to introduce the new
product.
Mrs. Lee has indicated that she does have alternative development
proposals, which are:
1.A reduced research program to see someone else comes out with the
product first and if not, then proceed with a crash program. The reduced
program for the first eight months would cost $10,000 per month. One advantage
of this is that if the effort was unsuccessful, then development costs would be
held to the eight-month figure (8 months X $ 10,000 = $80,000). The likelihood
of success under this approach is the same as the more orderly development.
(The likelihood of a competing company developing a product in 8 months is 60
percent.) The crash development program would take place in months 9 through 12
and would cost an additional $60,000. It would proceed only if the eight-month
study guaranteed a success.
2.Use a reduced research program and maintain an awareness of
industry developments to see if someone else develops a product. If someone
else has developed a product at the end of six months, it would cost only an
additional $30,000 to analyze their product and duplicate it. The reduced
development program would cost $10,000 per month.
Mr. Besnette, being the great marketer that he is, is of course
reluctant to be second on the market with a new product. He says that the first
product on the market will usually obtain a greater share of the market, and it
will be difficult to win those customers back. Consequently, he indicates that
only about 50 percent of the sales that he indicated in Table 1 could be
expected if Drink-at-Home waited until competing brands were already on the
market. Moreover, he suspects that there is only a 50/50 chance that the
competitor will be out with a product within the next six months.
There are four options: (1) orderly development of the pina
colada, (2) modest development effort followed by the crash program, (3) a
modest development effort for the first six months to see if a competitive
product comes on the market, and (4) do nothing.
TABLE 1 Sales and Profit Potentials
Consumer Acceptance
(Sales Potential) Probability Present
Values
(Discounted Value of Future Profits)
Substantial
0.10
$800,000
Moderate
0.60
$600,000
Low
0.30
$500,000
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Testing for Correlation and Bivariate Regression
Testing for Correlation and Bivariate RegressionYou had the chance earlier in the week to practice with the correlation an ...
Testing for Correlation and Bivariate Regression
Testing for Correlation and Bivariate RegressionYou had the chance earlier in the week to practice with the correlation and simple linear regression and obtain peer feedback. Hopefully you are excited about the potential these tests hold; equally important is that you recognize some of their weaknesses. Now, it is once again time to put all of that good brainstorming to use and answer a social research question with the correlation and simple linear regression. As you begin the Assignment, be sure and pay close attention to the assumptions of the test. Specifically, make sure that your variables are metric level variables that can easily be interpreted in these tests.For this Assignment, you will examine correlation and bivariate regression testing.To prepare for this Assignment:Review this week’s Learning Resources and media program related to regression and correlation.Using the SPSS software, open the Afrobarometer dataset or the High School Longitudinal Study dataset (whichever you choose) found in the Learning Resources for this week.Based on the dataset you chose, construct a research question that can be answered with a Pearson correlation and bivariate regression.Once you perform your correlation and bivariate regression analysis, review Chapter 11 of the Wagner text to understand how to copy and paste your output into your Word document.For this Assignment:Write a 2- to 3-paragraph analysis of your correlation and bivariate regression results for each research question. In your analysis, display the data for the output. Based on your results, provide an explanation of what the implications of social change might be.Use proper APA format, citations, and referencing for your analysis, research question, and display of output.
BUSN 311 American InterContinental Hypothesis Testing & Variance Research Paper
The below scenario describes a real-world or business application that utilizes statistical analysis to help resolve a bu ...
BUSN 311 American InterContinental Hypothesis Testing & Variance Research Paper
The below scenario describes a real-world or business application that utilizes statistical analysis to help resolve a business problem: increasing efficiency by decreasing processing time. Prepare an analysis by completing five steps of the hypothesis testing with one sample. The report should be a minimum of 5 pages in length.
Last week, your manager asked you to analyze staffing needs for the Foreclosure Department. She was so impressed, and she wants you to create another report for her. Her intention is to decrease the processing time per document.
Based on last week's report, the average number of processed documents per hour was 15.11, with a standard deviation of 2.666. That is, one document was reviewed in 238.25 seconds. To be objective as much as possible, the manager spoke with an employee whose average was exactly 15 documents per hour. The employee claimed that if she was given a larger monitor, the processing time would be shorter.
They conducted an experiment with a large monitor and measured processing time. After reviewing 20 documents, the calculated average processing time per document was 190.58 seconds. The manager believes that a bigger monitor helped reduce the processing time for reviewing foreclosure documents. Conduct a hypothesis test using a 95% confidence level, which means that significance level a = 0.05.
Use the 5-step process, and explain each term or concept mentioned in each section in the following.
Step 1: Set Up Null and Alternative Hypotheses
Based on the request description, explain if a one-tailed or two-tailed test is needed. If a one-tailed test is needed, is it a left or right-tailed test? Please explain why one alternative is better than the other.
State both of the following hypotheses:
Null hypothesis
Alternative hypothesis
You will need the following information to progress to Step 2:
Standard deviation: Explain what standard deviation is. Locate the calculated standard deviation in the assignment description, and enter here.
Random variable: Explain what a random variable is. Locate it in the assignment description, and enter here.
Test type: Compare and contrast t-test and z-test. Once done, determine which one is appropriate for the experiment given the fact that the sample size is less than 30.
Step 2: Decide the Level of Significance
Explain what the significance level is, and determine whether the one used in the assignment description is high, medium, or low. What does this significance level tell you about this test? Locate the level of significance in the given scenario, and list it in this step.
Significance level = ?
Determine the degree of freedom based on the number of reviewed documents in the new experiment (n = 20) and based on the formula Degree of freedom = n – 1.
Degree of freedom = ?
Critical value = (You will need to use the t-table and find the intersection point between the degree of freedom and the alpha value that is provided in the assignment description.)
Step 3: Calculate the Test Statistics
Calculate the test statistics based on the test type determined in Step 1.
If the determination was done correctly, you should use this formula to calculate the test statistics.
Test statistics = ?
Step 4: Compare the Calculated Test Statistics and the Critical Value
Construct a bell-shaped diagram showing the critical value and the calculated test statistic.
Step 5: Reach a Conclusion
Was the manager's conclusion correct? Share your conclusions on the assumptions in the scenario using the hypothesis testing that you conducted in the previous four steps.
Business Research Project
Is there a relationship between the sales of a product and the longevity of the product’s display with the type of mater ...
Business Research Project
Is there a relationship between the sales of a product and the longevity of the product’s display with the type of material used and time period of the display?
Statistics Exam 30 questions
1. Say you've obtained a chi-square of 12.56. You have a chi square critical value of 3.481. Based on this information ...
Statistics Exam 30 questions
1. Say you've obtained a chi-square of 12.56. You have a chi square critical value of 3.481. Based on this information, what do you conclude?A) Fail to reject the null hypothesis B) Reject the Null Hypothesis 2. Say you’ve obtained a chi-square of 10.95. You have a chi square critical value of 9.210. Based on this information, what do you conclude?A) Fail to reject the null hypothesis B) Reject the Null Hypothesis 3. For the table below, what would be the chi-square critical value if you were doing a hypothesis test and your significance level was 0.01? Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 A 3.841 B 6.635 C 5.991 D 9.210 4) For the table below, what is the expected frequency for Yes Demoted and Pretty Happy? (Remember that you don't need to do all the expected frequencies to get just one…) General Happiness Total Very Happy Pretty Happy Not Too Happy Were Demoted? Yes 5 12 7 24 No 294 545 99 938 Total 299 557 106 962 7 14 3 543 5. For the table below, what is the expected frequency for No Kids and Yes Counseling for Mental Problems? (Remember that you don’t need to do all the expected frequencies to get just one…) Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 42 16 692 259 6. For the table below, what is the expected frequency for No Demoted and Not too Happy? (Remember that you don't need to do all the expected frequencies to get just one…) General Happiness Total Very Happy Pretty Happy Not Too Happy Were Demoted? Yes 5 12 7 24 No 294 545 99 938 Total 299 557 106 962 7 292 103 543 7. For the table below, what is the expected frequency for No Kids and No Counseling for Mental Problems? (Remember that you don’t need to do all the expected frequencies to get just one…) Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 42 16 692 259 8. In the table below, what is the column marginal for “ever had home broken into = no”? Ever had home broken into? Gender Yes No Total Female 1558 1064 2622 Male 1567 1069 2636 Total 3125 2133 5258 3125 2133 2622 2636 9. For the table below, what is the chi-square? (Remember, you can round to whole numbers for the expected frequency, but leave at least 2 decimal places on for all other chi-square calculations). Counseling for Mental Problems Total Yes No Do you have Kids? Yes 39 695 734 No 19 256 275 Total 58 951 1009 0.04 0.94 0.36 0.82 10. For the table below, what is the chi-square? (Round this way or the answer will not turn out right: you can round to whole numbers for the expected frequency, but leave at least 2 decimal places on for all other chi-square calculations). Choose the answer that is closest. General Happiness Total Very Happy Pretty Happy Not Too Happy Were Demoted? Yes 5 12 7 24 No 294 545 99 938 Total 299 557 106 962 6.92 2.69 5.96 4.85 11. You've obtained a chi square of 34.56, and it's significant. You want to test how strong the relationship between these two variables is. You have a sample size of 75. You have a table with 2 rows and 4 columns. What's your Cramer's V? 0.46 0.68 0.26 0.53 12. Say you have a phi-coefficient of 0.51. How strong is the relationship between the two variables it tests? Weak Relationship Moderate Relationship Strong Relationship 13. You’ve obtained a chi square of 10.98, and it’s significant. You want to test how strong the relationship between these two variables is. You have a sample size of 50. What’s your phi-coefficient? 0.47 0.56 0.22 0.25 14. You’ve obtained a chi square of 16.52, and it’s significant. You want to test how strong the relationship between these two variables is. You have a sample size of 75. What’s your phi-coefficient? 0.47 0.22 0.69 0.18 15. Is the interpretation of the following regression line correct?Regression line: y ⏜ = 20.5 + 1.4 ( x ) Interpretation: For every one unit increase in y, there is a 1.4 increase in x. True False 16. Is the interpretation of the following regression line correct?Regression line: y ⏜ = 0.89 + 2.3 ( x ) Interpretation: For every one unit increase in y, there is a 0.89 increase in x. True False 17. Is the interpretation of the following regression line correct?Regression line: y ⏜ = 0.5 − 1.7 ( x ) " style="max-width: 694px;" rel="max-width: 694px;"> y ⏜ = 0.5 − 1.7 ( x ) Interpretation: For every one unit increase in x, there is a 1.7 decrease in y. True False 18. What type of relationship, positive or negative, is portrayed in the following sentence? When crime worsens, individuals' willingness to help their neighborhoods decreases. Positive Negative 19. What type of relationship, positive or negative, is portrayed in the following sentence? The statistical relationship shows that when foreclosure rates increase, crime worsens. Positive Negative 20. Find the correlation between the two following variables: % of people in neighborhood on welfare and the number of people who have police contact. x y 40 9 59 25 20 3 15 10 0.832 0.895 0.790 0.867 21. What is the strength of the following correlation? 0.156 Weak Moderate Strong 22. What is the strength of the following correlation? 0.451 Weak Moderate Strong 23. A friend of yours suggests that at least 10% of people at your university have had something stolen from them on campus in the past year. This is your population value. You take a random sample of 100 people in you classes to determine if your friend is correct, you think that they may be wrong. You find that 15% of them have had something stolen. Would you use z or t to test this hypothesis? Z Distribution T Distribution 24. A friend of yours suggests that at least 10% of people at your university have had something stolen from them on campus in the past year. This is your population value. You take a random sample of 100 people in you classes to determine if your friend is correct, you think that they may be wrong. You find that 15% of them have had something stolen. Would you have a one or two tailed test? One tailed Two Tailed 25. A friend of yours suggests that at least 10% of people at your university have had something stolen from them on campus in the past year. This is your population value. You take a random sample of 100 people in you classes to determine if your friend is correct. You find that 15% of them have had something stolen. What is the value of your test statistic? 1.667 2.112 1.521 1.231 26. What are the age differences among teens that report being delinquent (or not)? Conduct a two mean hypothesis test to ascertain whether there is an age difference between teens who report being delinquent and teens that report no delinquency. Use a significance level of α = 0.05 and the information below. No Delinquency Delinquent n = 21 n = 5 s1 = 0.6 s2 = 1.6 x1 = 13 x2 = 17 Would the alternative hypothesis for this test be directional or non-directional? Directional, greater than Directional, less than Non-Directional 27. Let’s say we believe that desk-officers and patrol-officers spend different get differing numbers of overtime hours because of their different assignments. We take a small sample of each group to determine if they are truly different. Conduct a two mean hypothesis test to ascertain whether there is a difference between desk-officers and patrol-officers regarding overtime. Use a significance level of α = 0.01 and the information below. Desk Officers Patrol Officers n = 4 n = 7 s1 = 2.9 s2 = 2.0 x ¯ 1 = 3 x ¯ 2 = 5 What do you conclude? Reject H0 Fail to Reject H0 28. Let’s say we believe that desk-officers and patrol-officers spend different get differing numbers of overtime hours because of their different assignments. We take a small sample of each group to determine if they are truly different. Conduct a two mean hypothesis test to ascertain whether there is a difference between desk-officers and patrol-officers regarding overtime. Use a significance level of α = 0.01 and the information below. Desk Officers Patrol Officers n = 4 n = 7 s1 = 2.9 s2 = 2.0 What is your critical value(s) for this test? ± 2.056 ± 2.365 ± 3.250 ± 2.831 29. Let’s say we believe that desk-officers and patrol-officers spend different get differing numbers of overtime hours because of their different assignments. We take a small sample of each group to determine if they are truly different. Conduct a two mean hypothesis test to ascertain whether there is a difference between desk-officers and patrol-officers regarding overtime. Use a significance level of α = 0.01 and the information below. Desk Officers Patrol Officers n = 4 n = 7 s1 = 2.9 s2 = 2.0 What is the degrees of freedom for this test? 9 11 8 6 30. What are the age differences among teens that report being delinquent (or not)? Conduct a two mean hypothesis test to ascertain whether there is an age difference between teens who report being delinquent and teens that report no delinquency. Use a significance level of α = 0.05 and the information below. No Delinquency Delinquent n = 21 n = 5 s1 = 0.6 s2 = 1.6 What is your obtained t? - 10.211 8.722 -9.430 -16.11
Drink-At-Home, Inc., Statistic and Probability homework help
Drink-At-Home, Inc.
Drink-At-Home, Inc. (DAH, Inc.), develops, processes, and markets
mixes to be used in nonalcoholi ...
Drink-At-Home, Inc., Statistic and Probability homework help
Drink-At-Home, Inc.
Drink-At-Home, Inc. (DAH, Inc.), develops, processes, and markets
mixes to be used in nonalcoholic cocktails and mixed drinks for home
consumption. Mrs. Lee, who is in charge of research and development at DAH,
Inc., this morning notified Mr. Dick Jones, the president, that exciting
developments in the research and development section indicate that a new
beverage, an instant pina colada, should be possible because of a new way to
process and preserve coconut. Mrs. Lee is recommending a major program to develop
the pina colada. She estimates that expenditure on the development may be as
much as $100,000 and that as much as a year's work may be required. In the
discussion with Mr. Jones, she indicated that she thought the possibility of
her outstanding people successfully developing such a drink now that she'd done
all the really important work was in the neighborhood of 90 percent. She also
felt that the likelihood of a competing company developing a similar product in
12 months was 80 percent.
Mr. Jones is strictly a bottom line guy and is concerned about the
sales volume of such a beverage. Consequently, Mr. Jones talked to Mr.
Besnette, his market research manager, whose specialty is new product
evaluation, and was advised that a market existed for an instant pina colada,
but was some-what dependent on acceptance by both grocery stores and retail
liquor stores. Mr. Besnette also indicated that the sales reports indicate that
other firms are considering a line of tropical drinks. If other firms should
develop a competing beverage the market would, of course, be split among them.
Mr. Jones pressed Mr. Besnette to make future sales estimates for various
possibilities and to indicate the present (discounted value of future profits)
value. Mr. Besnette provided Table 1.
Mr. Besnette's figures did not include (1) cost of research and
development, (2) cost of new production equipment, or (3) cost of introducing
the pina colada. The cost of the new production equipment is expected to be $
100,000 because of the special way the coconut needs to be handled, and the
cost of introducing the new product is expected to be about $150,000 because of
the point-of purchase displays that would be necessary to introduce the new
product.
Mrs. Lee has indicated that she does have alternative development
proposals, which are:
1.A reduced research program to see someone else comes out with the
product first and if not, then proceed with a crash program. The reduced
program for the first eight months would cost $10,000 per month. One advantage
of this is that if the effort was unsuccessful, then development costs would be
held to the eight-month figure (8 months X $ 10,000 = $80,000). The likelihood
of success under this approach is the same as the more orderly development.
(The likelihood of a competing company developing a product in 8 months is 60
percent.) The crash development program would take place in months 9 through 12
and would cost an additional $60,000. It would proceed only if the eight-month
study guaranteed a success.
2.Use a reduced research program and maintain an awareness of
industry developments to see if someone else develops a product. If someone
else has developed a product at the end of six months, it would cost only an
additional $30,000 to analyze their product and duplicate it. The reduced
development program would cost $10,000 per month.
Mr. Besnette, being the great marketer that he is, is of course
reluctant to be second on the market with a new product. He says that the first
product on the market will usually obtain a greater share of the market, and it
will be difficult to win those customers back. Consequently, he indicates that
only about 50 percent of the sales that he indicated in Table 1 could be
expected if Drink-at-Home waited until competing brands were already on the
market. Moreover, he suspects that there is only a 50/50 chance that the
competitor will be out with a product within the next six months.
There are four options: (1) orderly development of the pina
colada, (2) modest development effort followed by the crash program, (3) a
modest development effort for the first six months to see if a competitive
product comes on the market, and (4) do nothing.
TABLE 1 Sales and Profit Potentials
Consumer Acceptance
(Sales Potential) Probability Present
Values
(Discounted Value of Future Profits)
Substantial
0.10
$800,000
Moderate
0.60
$600,000
Low
0.30
$500,000
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