Find a formula for tan^2 theta solely in terms of sin^2 theta

tan = sin/cosNow cos2 = 1 - sin2 so cos = +/- sqrt(1 - sin2)In the second quadrant, cos is negative, so cos = - sqrt(1 - sin2)So that tan = sin/[-sqrt(1 - sin2)]or -sin/sqrt(1 - sin2)

http://www.answers.com/Q/What_is_tan_theta_in_terms_of_sin_theta_in_quadrant_II

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