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 how do i figure this out 

what represennts the zeros of the function g(x)= x 3 - 9x 2+ 2x + 48

Oct 1st, 2014

x3-9x2+2x+48

Put x= -2

-8-9*4+2*(-2)+48= -8-36-4+48=0

Hence (x+2) is a factor of x3-9x2+2x+48

(x3-9x2+2x+48) = (x+2)(x2-11x+24)= (x+2)(x2-8x-3x+24)=(x+2)[x(x-8)-3(x-8)]

=(x+2)(x-3)(x-8)

Hence (x+2)(x-3)(x-8)=0

x+2=0 or x-3 =0 or x-8 =0

x=-2 or x =3 or x =8


Oct 1st, 2014

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