how do i figure this out
what represennts the zeros of the function g(x)= x 3 - 9x 2+ 2x + 48
Put x= -2
Hence (x+2) is a factor of x3-9x2+2x+48
(x3-9x2+2x+48) = (x+2)(x2-11x+24)=
x+2=0 or x-3 =0 or x-8 =0
x=-2 or x =3 or x =8
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