Time remaining:
##### Use a graph to find how many minutes will have passed before Amy catches Marisol.

label Algebra
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schedule 1 Day
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Marisol will run 10 minutes per hour and Amy will start 5 minutes later running at 8 minutes per hour. The equations for the runners are given as follows, for which M(x) = Marisol and A(x) = Amy

Oct 4th, 2014

If the equations are:

M(x) = 1/10 x

A(x) = 1/8 (x-5)   where x is in min and M(x) and A(x) are in miles:

Both are linear equations. You have to find where both lines meet.

M(x) = A(x)

1/10 x = 1/8 (x-5)

1/10 x = 1/8 x - 5/8  (distributive property)

1/10 x - 1/8 x = -5/8  (regrouping the x)

(1/10 - 1/8) x = -5/8

(4/40 - 5/40) x = -5/8   (common denominator is 40)

-1/40 x = -5/8    (you can eliminate the negative signs)

x = 5*40/8 = 200/8 = 25 min

Marisol and Amy meet at 25 minutes.

If you want to know at what distance they meet:

M(25) = 1/10 (25) = 2.5 miles

Oct 4th, 2014

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Oct 4th, 2014
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Oct 4th, 2014
Sep 20th, 2017
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