A 0.3126 g sample of h2c2o4 requires 26.21 ml of particular concentration of NaOH to complete the following reaction. what is the molarity of NaOH
The molar mass of oxalic acid is 90.04 g mol-1
2NaOH(aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O(aq)
From the balanced equation the reacting ratio of NaOH to
C2O42- is 2:1
i.e moles of NaOH / moles of C2O42- = 2/1
i.e MNaOH × VNaOH = 2/1 × moles of C2O42-
i.e. MNaOH = 2/1 × moles of C2O42-/ VNaOH
= 2/1 × (0.3126 g /90.04 g mol-1) / 0.02621 dm-3
= 0.2649 mol dm-3
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