A rock is thrown straight up with an initial velocity of 24.5 m/s. What maximum height will the rock reach before starting to fall downward? (Take acceleration due to gravity as 9.80m/s squared)

The initial velocity =24.5 m/s

When it reaches maximum height, the velocity will be 0 m/s

The time taken to reach the maximum height = 24.5m/s/(9.8m/s^2)=2.5 seconds

The maximum height = ut+1/2 at^2= 24.5*2.5+0.5*9.8*2.5^2=61.25+30.625 =91.875

Answer 91.875 m = 91.9 m or 92 m

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