y=-x^2-x+6

y=x^2-x+6

dy/dx = 2x-1

dy/dx=0 when 2x-1=0 i.e x= 1/2

d2y/dx2=2 >0

Hence this is minimum at x=1/2

Maximum value of x^2-x+6 will be at infinity. If an interval (a,b) is given it will be at b provided b>1

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