An urn contains six red balls, five black balls, and four green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red ball and a black ball will be selected? My book says the answer is 2/7.
what is the probability that a red ball and a black ball will be selected
P(B) and P(W)= 6/15*5/14=1/7
P(W) and P(B)= 5/15*6/14= 1/7
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?