A plane is flying horizontally with speed
239 m/s at a height 4820 m above the ground,
when a package is dropped from the plane.
The acceleration of gravity is 9.8 m/s
assuming no air friction, we know that the horizontal velocity does not change since there are no horizontal forces this means we know the horizontal velocity is constant at 239 m/s throughout the flight, since the package has the same horizontal velocity as the plane then horizontal distance = horizontal velocity x time we find the time from dist = 1/2 gt^2 where g=9.8 m/s^2 and dist = height = 4820 m t = sqrt[2*4820 m/9.8m/s^2] = 31.36 s so the horizontal distance = 239 m/s x 31.36 s = 7495.04 m
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