A plane is flying horizontally with speed

239 m/s at a height 4820 m above the ground,

when a package is dropped from the plane.

The acceleration of gravity is 9.8 m/s

2

.A second package is thrown downward from

the plane with a vertical speed v1 = 59 m/s.

horizontal dist = horizontal velocity x time

we find the time from

dist = 1/2 gt^2 where g = 9.8 m/s^2 and distance = height = 4820 m

t = √[2*4820 m /9.8 m/s^2] = 31.36 s

so the horizontal distance = 239 m/s x 31.36 s = 7495.04 m

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