A plane is flying horizontally with speed
239 m/s at a height 4820 m above the ground,
when a package is dropped from the plane.
The acceleration of gravity is 9.8 m/s
.A second package is thrown downward from
the plane with a vertical speed v1 = 59 m/s.
horizontal dist = horizontal velocity x time
we find the time from
dist = 1/2 gt^2 where g = 9.8 m/s^2 and distance = height = 4820 m
t = √[2*4820 m /9.8 m/s^2] = 31.36 s
so the horizontal distance = 239 m/s x 31.36 s = 7495.04 m
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