A marble is fired horizontally from a launching device attached to the edge of a tabletop which is 94.0 cm above the floor. The marble then strikes the floor 2.35 meters from the edge of the table. Show your work please.
h = 94 cm = 0.94 m
X = 2.35 m
h = 1/2 gt^2 then
t = √2*h/g
t = √2 * 0.94 /9.8
t = 0.44 sec
X = Vx * t where Vx is the horizontal veloccity
Vx = X / t
Vx = 2.35 / 0.44
Vx = 5.341 m/s
Hence the horizontal velocity is 5.341 m/s.
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?