c programming , collatz series, programming assignment help

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I wrote this code that is suppose to give the collatz series of the numbers from the user.

the program should be able to take infinite number of arguments and then prints each number in a line followed by a colon followed by the collatz series of that number separated by a space with no leading spaces.

I still couldn't figure out how to take many arguments from the user. I know I have to use a while loop but I don't know what to write inside it.   


#include<stdio.h>

int collatz(int x, int y){

 // base case

 if(y<x)

  return y;

 //if n is even

 else if(n%2==0){

  y=y+1;

  x=x/2;

  printf("%d\n", x);

  collatz(n,k);

 }

 //if n is odd

 else {

  y=y+1;

  x= 2*x +1;

  printf("%d\n", x);

 }

}


int main(){

 //the input 

 int n;

 //counter

 int i;


 while(scanf("%d", &n) !=EOF){

 }

 scanf("%d", n);

 //printing the series of numbers

 printf("%d", collatz(n,i));

 return 0;

}


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Explanation & Answer

All coding has been attached.

#include
#include
int collatz(int);
v...


Anonymous
This is great! Exactly what I wanted.

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