PLEASE HELP WITH 10 and 11

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Oct 9th, 2014

You know length of two sides for each wire 

Length of first wire = L cos thetha = 10 cos37 = 10 x 0.7986 = 7.986 m

Length of second wire = L cos thetha = 10 cos 47 = 10 x 0.6819 = 6.819 m 


Please check this one . 

For second one use phythagoras theroem,

A^2+B^2=C^2

IN ORDER TO FIND THE LENGTH OF L PORTION first you have to find out the length of imaginary line . 

lets take that imaginary line as C

A=10

B=13

therefore C^2=A^2+B^2

C^2=10^2+13^2 = 100 +169 =269

C^2=269

C=SQRT 269=16.40 cm


now to find L , longest piece

L^2 =C^2 + D^2   

L^2= (16.40)^2 + (8)^2

L^2= 268.96+64=332,96

L=SQRT 332.96

L=18.24cm                               take D=8cm


cos thetha = base/ hypotenuse

cos thetha = 16.40/18.24= 0.8987

thetha= cos inverse 0.8987

thatha= 26.00 degres


 


Oct 10th, 2014

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