You know length of two sides for each wire
Length of first wire = L cos thetha = 10 cos37 = 10 x 0.7986 = 7.986 m
Length of second wire = L cos thetha = 10 cos 47 = 10 x 0.6819 = 6.819 m
Please check this one .
For second one use phythagoras theroem,
IN ORDER TO FIND THE LENGTH OF L PORTION first you have to find out the length of imaginary line .
lets take that imaginary line as C
C^2=10^2+13^2 = 100 +169 =269
C=SQRT 269=16.40 cm
now to find L , longest piece
L^2 =C^2 + D^2
L^2= (16.40)^2 + (8)^2
L=18.24cm take D=8cm
cos thetha = base/ hypotenuse
cos thetha = 16.40/18.24= 0.8987
thetha= cos inverse 0.8987
thatha= 26.00 degres
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?