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Chemistry
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Calculate the following in 8.28 g Li3PO4

a)  Li+ ions=    Li+ ions

b) grams O=    g O

Oct 2nd, 2014


b) grams O = 8.28g (mass of O in one mole)/(total molar mass)= (8.28g)x(64g/mol)/(115.79g/mol)=4.58g O

 

a) Li+ ions = (8.28g)/(115.79g/mol)= 0.715 mol

(0.715 mol) x (6.02x10^23 molecules/mol) x (3 Li+ ions/molecule) = 1.29 e23 Li+ ions

 

 

Oct 11th, 2014

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