Á ball is projected from the top of a 92.0 meter high cliff with the initial speed of 19.8 m/s determine (á) the horizontal displacement and (b) the final speed the the instant prior to hitting the ground.

DATA :

h = 92 m

u = 19.8 m/s

X = ?

v = ?

SOLUTION :

t = √2h/g

t = √2*92/9.8

t = √18.77

t = 4.33

Now

X = u * t

X = 19.8 * 4.33

X = 85.8 m

v = √(u^2 + 2gh)

v = √(19.8^2 + 2*9.8*92)

v = √2195.24

v = 46.85 m/s

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up