The angular speed of the rotor in a centrifuge increases from 422 to 1411 rad/s in a time of 5.10 s.

A.Obtain the angle through which the rotor turns.

B.What is the magnitude of the angular acceleration?

A. (1411-422) rad/s * 5.10 s = 989*5.1=5043.9 =5044 radian

B. (1411-422)rad/s divided by 5.1 s=989/5.1 =193.92 radian/second^2

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