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What is the length of the horizontal axis of this ellipse?

Algebra
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(x-4)^2/5^2+(y+2)^2/6^2=1

Oct 13th, 2014

(x-4)^2/5^2+(y+2)^2/6^2=1

Standard form of equation is (x-h)^2/a^2 + (y-k)^2/b^2 = 1 Where p(h,k) is the center . a and b are the respective vertices distance from the center is ±√a^2 - b^2   and foci distances from center a>b

%28x-4%29%5E2%2F5%5E2+%2B+%28y%2B2%29%5E2%2F6%5E2=1 C=(4,-2) Length of the horizontal axis is 10.

Oct 13th, 2014

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