Find the surface area of the following to the nearest 10th of a unit.

Mathematics
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Oct 13th, 2014

d. Surface Area of a Cylinder = 2 pi r 2 + 2 pi r h

r=10 

h= 12 

2(3.14)()+2(3.14)(10)(12)

6.28*100+6.28(120)

628+753.6= 1,381.6

c. 4 pi r^2 

4(3.14)(19^2)

12.56*361= 4,536.46

Oct 13th, 2014

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