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What is the centripetal acceleration at a point that is 0.058 m from the center

Physics
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A computer is reading data from a rotating CD-ROM. At a point that is 0.031 m from the center of the disc, the centripetal acceleration is 126 m/s2. What is the centripetal acceleration at a point that is 0.058 m from the center of the disc?

Oct 16th, 2014

If w is the angular speed of the disk, the centripetal acceleration at a distance r from the center is: 

a = rw^2. 

w^2 = a / r 

As w is constant for the whole disc: 

a1 / r1 = a2 / r2 

a2 = r2 a1 / r1. 

Putting     r1 = 0.031 m,     a1 = 126 m/s^2,    r2 = 0.058 m: 

a2 = 0.058 * 126 / 0.031 

= 236 m/s^2.

Oct 16th, 2014

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