##### Any help would be appreciated.

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When CaCO3 is added to HCl, CaCl2, CO2, and H2O are produced.

CaCO3(s)+2HCl(aq)=>CaCl2(aq)+H2O(l)+CO2(g)

How many g of CaCl2 will be made when 27g CaCO3 are combined with 12g HCl?

__gCaCl2

Which reactant is in excess and how many g of this reactant will remain after the reaction is complete?

__g of CaCO3 or HCl?

Oct 16th, 2014

Molar mass of CaCO3 is 100.1g

therefore moles of CaCO3 reacting= 27g/100.1g

=0.2697moles

moles of HCl reacting=12g/36.5g   molar mass of HCl is 36.5g

=0.3287moles

since mole ratio is 1:2,it means CaCO3 is in excess, therefore the amount that reacted was

1/2*0.3287

0.1644moles

therfore moles of CaCl2 is 0.1644 moles, But since molar mass of CaCl2 is 110.984 g

grms of CaCl2 will be 0.1644 moles * 110.984

=18.24grams

the excess reactant is CaCO3 BY

0.2697moles-0.1644moles

0.1053 M *100.1g

=10.54 grams

Oct 16th, 2014

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Oct 16th, 2014
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Oct 16th, 2014
May 22nd, 2017
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