How many g of CaCl2 will be made when 27g CaCO3 are combined with 12g HCl?
Which reactant is in excess and how many g of this reactant will remain after the reaction is complete?
__g of CaCO3 or HCl?
Molar mass of CaCO3 is 100.1g
therefore moles of CaCO3 reacting= 27g/100.1g
moles of HCl reacting=12g/36.5g molar mass of HCl is 36.5g
since mole ratio is 1:2,it means CaCO3 is in excess, therefore the amount that reacted was
therfore moles of CaCl2 is 0.1644 moles, But since molar mass of CaCl2 is 110.984 g
grms of CaCl2 will be 0.1644 moles * 110.984
the excess reactant is CaCO3 BY
0.1053 M *100.1g
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