I'm so confused how to you solve for the x intercepts in these equations? I couldn't find a way to factor it in a way that makes sense.... x^2-6x+3 and the other equation is 3x^2+2x=x^2+9X-3
2x(x-3)-1(x-3) = 0
(x-3) (2x-1) = 0
x-3=0 or 2x-1 = 0
x=3 or 2x=1
x=3 or x=1/2
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