CHEM 1101 ISU Chemistry Molar Concentration and Colligative Properties Worksheet

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Serfusyna

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CHEM 1101

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Hello, I attached a PDF that contains the questions for this assignment. It is pretty straight forward, its just the questions need to be answered. Thank you!

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CHEM 1101 Homework Assignment #9 Chapter 9.2-9,4 Due: Monday, November 9 by 11:59 pm 1.) A solution was prepared by dissolving 10.0 g K3PO4 in a solution with a total volume of 250.0 mL. What is the molar concentration (molarity) of this solution? 2.) How many mL of a 0.100 M Ca(NO3)2 solution are needed to provide 0.500 g of Ca(NO3)2 ? 3.) Calculate the osmolarity (osm/L) of each of the following solutions: a.) 0.25 M CH3CH2OH b.) 0.45 M (NH4)2CO3 c.) 0.60 M KOH 4.) True or False. A 0.24 M NaCl solution will have the same colligative properties as a 0.16 M CaBr2 solution. 5.) For each pair, which one of the two solutions is expected to have the higher boiling point? a.) 0.10 M C6H12O6 vs. 0.050 M Mg(NO3)2 b.) 0.25 osm/L CuSO4 vs. 0.20 M LiF 6.) True or False. In osmosis, solvent molecules (e.g., water) pass through a semipermeable membrane from the solution of higher osmolarity to the solution of lower osmolarity. 7.) True or False. An irreversible reaction goes both ways.
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CHEM 1101
Homework Assignment #9
Chapter 9.2-9,4
Due: Monday, November 9 by 11:59 pm
1.) A solution was prepared by dissolving 10.0 g K3PO4 in a solution with a total volume of
250.0 mL. What is the molar concentration (molarity) of this solution?
K3PO4 MW=212.264 g/mol
Mass K3PO4= 10.0 g
𝑛=

π‘šπ‘Žπ‘ π‘  (𝑔)
10.0𝑔
𝑔 ; 𝑛 = 212.264𝑔/π‘šπ‘œπ‘™ = 0.471 π‘šπ‘œπ‘™
π‘€π‘Š(
)
π‘šπ‘œπ‘™

Volume solution= 250 mL
250 π‘šπΏ Γ—

𝑀=

1𝐿
= 0.25𝐿
1000 π‘šπΏ

𝑛 (π‘šπ‘œπ‘™)
0.471 π‘šπ‘œπ‘™
=
= 𝟎. 𝟏...


Anonymous
Great study resource, helped me a lot.

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