When 108 g of water at a temperature of 22.5 oC is mixed with 65.1 g of water at an unknown temperature results in a final temperature of the mixture of 47.9 oC. What was the temperature of the second sample of water
Let t be the temperature.
Since water is involved , the specific heat of water included on both sides will get cancelled and hence
108(47.9-22.5) = 65.1(t-47.9)
t =47.9+42.1= 90
Answer: 90 degrees.
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