What is the grams of solute needed to prepare the following solutions in1.2L of a 3.0M NaOH solution
Molarity of solution = 3.0 M
Volume of Solution = 1.2 L
Moles of NaOH required = Molarity * Volume = 3.0 * 1.2 = 3.6 moles
Mass of NaOH required = Moles of Na OH * Molar mass of NaOH
Mass of NaOH required = 3.6 * 40 = 144 grams (Answer)
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