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What's the normal force of the seat pushing upward on the boy?

Physics
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A boy of mass 80 kg is riding a ferris wheel. The radius of the wheel is 30 meters and the speed of the rider is 5m/s. When at the bottom of the ride, find the normal force of the seat pushing upward on the boy.

Oct 20th, 2014

Well the force were talking about here is the combined addition of the normal force and Centripetal force of the person. The forces add together because their in the same direction ( the normal force is pointing up and the ferris wheel is pointing toward the center of the wheel so also pointing up) The normal force is equal to the mass times the gravitational acceleration and the centripetal force is equal to (MV^2)/R where M is mass V is their tangential velocity and R is the radius of the wheel. 

Now that thats all out of the way we need to do the math for the normal force. So Fn=(normal force)

Fn=Mg+(MV^2/R)

now if im correct this should give you your answer. oh and g is the gravitational acceleration 9.8 m?s^2

Oct 21st, 2014

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