The excursion boat on the river takes 2 1/2 hours to make the trip to a point 12 miles upstream and to return. If the rate at which the boat travels in still water is 5 times the rate of the river current, what is the rate of the current?
As I understand from the problem that the givens are for the boat in still water, and I will solve it accordingly.
Rate = change/unit time, for this problem since the distance changes and time is in hours,
the rate = distance in miles/ hour
Total distance traveled by the boat = 12 * 2 = 24 miles. (upstream and back)
? miles in 1 hour
The rate at which the boat travels = 24 * 1 / 2.5 = 9.6 miles/hour
Assume the rate of current = x, then the rate of travel in still water = 5x
Therefore, 5x = 9.6
x = 9.6/5 = 1.92 miles/hour
This means that current moves 1.92 miles each hour. (the river's velocity)
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