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Algebra 2 Substitution

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Not really sure what to put, it's simple substitution with two equations. I have no idea at all how to do it.

Oct 22nd, 2014

Ok, without the equations, I will try to make this as encompassing as possible. Say you have an equation of 4x+y=16 & 12x+4y=52, you can solve these with "simple substitution." 

To do this type of problem, you pick one of these equations and solve it for one of the equations. I will take the first equation and solve it for y.

Doing this leaves y=16-4x. 

Now plug this into the second equation and replace the "y" with "16-4x" and solve for x to get a numerical value. 

Ex:

12x + 4(16-4x) = 56

12x + 64 - 16x = 52

-4x = -12

x=3


Now you take this "x=3" value and plug it into the other equation and solve for y.

4(3) + y = 16

y=4

So now you have x=3 and y=4. Now you're done!


Hope this helps.

Oct 22nd, 2014

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Oct 22nd, 2014
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