Select the graph of the quadratic function ƒ(x) = 4 - x2. Identify the vertex and axis of symmetry., JC Week 4 assignment help

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timer Asked: Oct 4th, 2016
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Question Description

QUESTION 1

  1. Select the graph of the quadratic function ƒ(x) = 4 - x2. Identify the vertex and  axis of symmetry.

    Vertex: (0,4)

    Axis of symmetry: y-axis

    Vertex: (0,2)

    Axis of symmetry: y-axis

    Vertex: (0,5)

    Axis of symmetry: y-axis

    Vertex: (0,3)

    Axis of symmetry: y-axis

    Vertex: (0,1)

    Axis of symmetry: y-axis

5 points  

QUESTION 2

  1. Select the graph of the quadratic function ƒ(x) = x2 + 3.  Identify the vertex and axis of symmetry.

    Vertex: (0,4)

    Axis of symmetry: y-axis

    Vertex: (0,5)

    Axis of symmetry: y-axis

    Vertex: (0,1)

    Axis of symmetry: y-axis

    Vertex: (0,3)

    Axis of symmetry: y-axis

    Vertex: (0,2)

    Axis of symmetry: y-axis

5 points  

QUESTION 3

  1. Determine the vertex of the graph of the quadratic function

5 points  

QUESTION 4

  1. Determine the x-intercept(s) of the quadratic function

    ƒ(x) = x2 + 4x - 32

    (-4,0), (8,0)

    (0,0), (7,0)

    (4,0), (-8,0)

    (0,0), (-7,0)

    no x-intercept(s)

5 points  

QUESTION 5

  1. Write a polynomial that fits the description.

    A fifth-degree polynomial with leading coefficient 4

    1024x5 + 3x + 1

    4x5 + 3x + 1

    4x4 + 3x3 + 4x2 + 5x + 1

    6x5 + 3x + 1

    x5 + 4

5 points  

QUESTION 6

  1. Perform the operation and write the result in standard form.

    (3x2 + 5) - (x2 - 4x + 5)

    3x2 + 4x

    2x2 + 4x + 5

    2x2 - 4x

    2x2 + 4x

    2x2 + 4x - 5

5 points  

QUESTION 7

  1. Multiply or find the special product.

    (x+4)(x+9)

    x2 + 13x

    x2 + 4x + 36

    x2 + 36

    x2 + 13x + 36

    x2 + 13x + 9

5 points  

QUESTION 8

  1. Factor out the common factor.

    8x3 - 104x

    8x3(1-13x)

    8(x3-13x)

    8x2(x-13)

    x(8x2-104)

    8x(x2-13)

5 points  

QUESTION 9

  1. Factor the Trinomial.

    x2 + 14x + 45

    (x-5)(x-9)

    (x+5)(x-9)

    (x+5)(x+9)

    (x-5)-(x-9)

    (x-5)(x+9)

5 points  

QUESTION 10

  1. Determine whether the value of x=0 is a solution of the equation.

    5x-3 = 3x+5

    yes

    no

5 points  

QUESTION 11

  1. Solve the equation and check your solution.

    67x - 24 = 3x + 8(8x-3)

    3

    67

    -3

    -67

    All real numbers

5 points  

QUESTION 12

  1. Solve the quadratic equation by factoring.

    x2 - 6x + 5 = 0

    -1,5

    -1,-5

    1,-5

    1,5

    6,5

5 points  

QUESTION 13

  1. Solve the equation and check your solution. (If not possible, explain why)

    8

    7/17

    15/8

    12

    15

5 points  

QUESTION 14

  1. Find the slope-intercept form of the equation of the line that passes through the given point and has the indicated slope m.  Sketch the line.

    (-6,6), m=-2

    y=6x+6

    y=6x+6

    y = -6x-6

    y = -2x - 6

    y = 6x-6

5 points  

QUESTION 15

  1. Evaluate the function  at q(3)

    1/8

    1/6

    1/4

    1/7

    1/5

5 points  

QUESTION 16

  1. Does the table describe a function?

    yes

    no

5 points  

QUESTION 17

  1. Find the domain of the function.

    All real numbers x

    Non-negative real numbers x such that x = 0

    Non-negative real numbers x

    All real numbers x such that x<0

    All real numbers x such that x>0

5 points  

QUESTION 18

  1. Find the zeroes of the function algebraically.

    ƒ(x) = 2x2 - 3x - 20

    -5/2, 4

    -5/2, -4

    -2/5, 4

    5/2, -4

    5/2, 4

5 points  

QUESTION 19

  1. Find (f+g)(x)

    ƒ(x) = 2x - 4, g(x) = 6 - x

    3x - 2

    2x - 2

    2x + 2

    3x + 2

    x+2

5 points  

QUESTION 20

  1. Find g ∘ f

    ƒ(x) = x3, g(x) = x - 1

    x3 - 1

    x3

    (x - 1)3

    (x3 + 1)

    (x + 1)3

5 points  

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Tutor Answer

soph_0001
School: Cornell University

Hi! I've attached the complete solution, with the answers (I used letters A to E to indicate which is the correct one among the ones you listed) and the details about how to get to the solution.Let me know if you need further details :)Have a nice evening!

The first exercises ask to calculate the vertex and axis of symmetry of a parabola. This can be done
2
b
b
using the formula V = (− 2a
; − b −4ac
4a ) and axis x = − 2a .

Question 1
f (x) = 4 − x2
Parameters are a = −1, b = 0, c = 4. The vertex is V = (0; 4) and the axis of symmetry is x = 0.
Answer is A.

Question 2
f (x) = x2 + 3
Parameters are a = 1, b = 0, c = 3. The vertex is V = (0; 3) an...

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Anonymous
Excellent job

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