A boy of mass 80 kg is riding a ferris wheel. The radius of the wheel is 30 meters and the speed of the rider is 5m/s. When at the bottom of the ride, find the normal force of the seat pushing upward on the boy.
Fn = (mass)(acceleration)
Acceleration = Velocity / Time -First we need to find time, in seconds, it took to get around the ferris wheel.
Circumference = pi(diameter)
=60pi (meters) -Now we can solve for time.
T = Distance / Velocity
= 60pi (m) / 5(m/s)
=37.699 (s) -Now we can solve for acceleration.
A = 5 (m/s) / 37.699 (s)
= 0.133 (m/s^2)
Fn = 80 (kg) x 0.133 (m/s^2)
Fn = 10.64 N
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