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What's the normal force of the seat pushing upward on the boy?

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A boy of mass 80 kg is riding a ferris wheel. The radius of the wheel is 30 meters and the speed of the rider is 5m/s. When at the bottom of the ride, find the normal force of the seat pushing upward on the boy.

Oct 20th, 2014

Fn = (mass)(acceleration)

Acceleration = Velocity / Time  -First we need to find time, in seconds, it took to get around the ferris wheel.

Circumference = pi(diameter)

= pi(60m)

=60pi (meters)  -Now we can solve for time.

T = Distance / Velocity

= 60pi (m) / 5(m/s)

=37.699 (s)  -Now we can solve for acceleration.

A = 5 (m/s) / 37.699 (s)

= 0.133 (m/s^2)

Fn = 80 (kg) x 0.133 (m/s^2)

Fn = 10.64 N

Oct 24th, 2014

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Oct 20th, 2014
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