a student brought 25.73g of iron (cp=.449) at 23.2degrees Celsius into contact with 50.82g of silver (cp=.235) at 68.8 degrees Celsius. determine the equilibrium temperature
Let the equilibrium temperature be t
25.73*0.449*(t-23.2) = 50.82*0.235*(68.8-t)
t( 11.55277+11.9427) = 11.55277*23.2+11.9427*68.8
t = (268.0243+821.6578)/23.49547=1089.682/23.49547 =46.38
Answer: 46.38 degrees celsius
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