Write the equation of a line through (2/3, 3/4) that is perpendicular to y=-3/5x+2
y=-3/5x+2 has slope or gradient = -3/5
The line perpendicular to this has gradient 5/3 (the product of the two gradients must equal -1)
Hence equation of required line is of the form y = 5/3 x + c
To find c substitute the values of the given point (x=2/3 and y=3/4) to get
3/4 = 5/3 * 2/3 + c
c= 3/4 - 10/9
= 27/36 -40/36
The required equation is y = 5/3 x - 13/36
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