Write the equation of a line through (2/3, 3/4)

Algebra
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Write the equation of a line through (2/3, 3/4) that is perpendicular to y=-3/5x+2

Oct 26th, 2014

 y=-3/5x+2  has slope or gradient = -3/5

The line perpendicular to this has gradient 5/3   (the product of the two gradients must equal -1)

Hence equation of required line is of the form y = 5/3 x + c

To find c substitute the values of the given point   (x=2/3 and y=3/4) to get

3/4 = 5/3 * 2/3 + c

c= 3/4 - 10/9

 = 27/36 -40/36

= -13/36

The required equation is y = 5/3 x - 13/36

Oct 26th, 2014

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