Please help me answer this.

Chemistry
Tutor: None Selected Time limit: 1 Day

1.719g sample of CaCO3 mixture is thermally decomposed,producing CaO(s)&CO2(g).After reaction,mixture has mass of 1.048g.

How many grams&moles of CO2 are evolved?

How many moles&grams of CaCO3 are in mixture?

What is the percent CaCO3 in the mixture?

Oct 26th, 2014

 

the mas of CO2 is=1.719-1.048 since it only esacpes as it is gas

=0.671gm

mass number CO2 is =12+16*2
                           =44
moles = mass/mass number
=0.671/44
=0.01524 moles

mass number of CaCO3=40+12+3 x16
  =100
the  mole ration for the reaction is 1:1 thus
moles CaCO3 involved in reaction is 0.01524 moles.

mass=moles x mass number
  =0.01524 x 100
 =1.524
percantage of CaCO3
is
(1.524/1.719 ) x 100%
=88.66%




Oct 26th, 2014

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Oct 26th, 2014
...
Oct 26th, 2014
Dec 8th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer