Please help me answer this.

Tutor: None Selected Time limit: 1 Day

1.719g sample of CaCO3 mixture is thermally decomposed,producing CaO(s)&CO2(g).After reaction,mixture has mass of 1.048g.

How many grams&moles of CO2 are evolved?

How many moles&grams of CaCO3 are in mixture?

What is the percent CaCO3 in the mixture?

Oct 26th, 2014


the mas of CO2 is=1.719-1.048 since it only esacpes as it is gas


mass number CO2 is =12+16*2
moles = mass/mass number
=0.01524 moles

mass number of CaCO3=40+12+3 x16
the  mole ration for the reaction is 1:1 thus
moles CaCO3 involved in reaction is 0.01524 moles.

mass=moles x mass number
  =0.01524 x 100
percantage of CaCO3
(1.524/1.719 ) x 100%

Oct 26th, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Oct 26th, 2014
Oct 26th, 2014
Mar 28th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer