Description
A car and a bus set out at 2p.m. from the same point, headed in the same direction. The average speed of the car is30mph slower than twice the speed of the bus. In two hours, the car is 20miles ahead of the bus. Find the rate of the car.
Please explain how you arrived at your answer.
Explanation & Answer
This problem is going to rely on the distance formula. d=rt (distance = rate * time) If we define the speed of the car as "c" and the speed of the bus as "b" then we can translate our problem statement into an equation. In equation form we have c=2b-30 (The speed of the car = twice the speed of the bus - 30mph)Next we will create an equation for the car being 20 miles ahead of the bus after 2 hours. This equation will be set up using the distance formula. We will use rate and time to create distances that we can compare in relation to the distance the car has covered. (distance the car covered)=(distance the bus covered)+(distance between the car and the bus)c*2 = b*2 +20 (speed of the car)(time elapsed)=(speed of the bus)(time elapsed)+(dist...
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