Calculate the molarity of the following solutions

label Chemistry
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a) 21.1 g of KCL in 500. mL solution

b) 44.5 g NaOH in 2.00 L

c) 41.5 mg ammonium phosphite in 3.5 mL Solution

Oct 28th, 2014

KCL mass = 39.09+35.453 = 74.543

Molarity = 21.1/74.543 * 0.5 = 0.1415

NaOH=22.99+16+1=39.99

Molarity =41.5/39.99 * 2 =2.2256

(NH4)3 PO4= 3(14+4)+30.97+16*4 = 54+64+30.97 =148.97

Molarity =41.5/148.97 *0.0035 =0.000975

Oct 28th, 2014

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Oct 28th, 2014
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