for the reaction 2 C2H6(g) + 7O2(g) = 4 CO2(g) + 6 H2)(g)

If the rate of disappearance of ethane (C2H6) is o.740 what is the rate of disappearance of oxygen

I assume your rate is mol per s or cm3 per s? You can work with mol or cm3 in this.

The stoichiometry (balancing) in the equation shows that 2 mol of C2H6 reacts with 7 mol of O2.

Therefore the rate of consumption of O2 will be 7/2 times that of C2H6.

So your answer is 7/2 x 0.740 = 2.590 (whatever units you are using).

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