15.1 L N2 at 25°C and 125 kPa and 37.1 L O2 at 25°C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is the total pressure at 59°C?

15,1 L N2 at 25 °C and 125 kPa - - - - - - - - - - - - - - - - - - - - - - - 25°C = (273.15+25) = 298,15 °K P x V = n x R x T . . . then : n(N2) = P x V / (R x T) n(N2) = 125•10^{3} x 15.1•10^{-3} / (8.314 x 298.15) n(N2) = 0.7614 mole of N2 37.1 L O2 at 25 °C and 125 kPa - - - - - - - - - - - - - - - - - - - - - - - - n(O2 ) = P x V / (R x T) n(O2 ) = 125•10^{3} x 37.1•10^{-3} / (8.314 x 298.15) n(O2 ) = 1.8708 mole of O2 The total pressure at 59 °C P(total) = n(total) x R x T / V(final) P(total) = (0.8825 +2.234) x 8.314 x 332,15 / 6.25•10^{-3} P(total) = 1.163•10^6 Pascal

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