A 6.62-L cylinder contains 1.18 mol of gas A and 3.84 mol of gas B, at a temperature of 32.0 °C.Calculate the partial pressure of each gas in the cylinder.Assume ideal gas behavior.

PA=____kPA PB=____kPA

What is the total pressure?

PTotal=____kPA

To calculate the partial pressure of each gas:

Partial pressure = (mol gas) * (R) * (Temp in K) / (volume in L)

PA = (1.18 mol)*(0.08206 Latm/molK)(305.15 K) / (6.62L) = 4.46 atm

PB = (3.84 mol)*(0.08206 Latm/molK)(305.15K) / (6.62 L) = 14.53 atm

Ptoal = PA + PB = 4.46 + 14.53 = 18.99 atm

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