Any help would be greatly appreciated.

Chemistry
Tutor: None Selected Time limit: 1 Day

A 6.62-L cylinder contains 1.18 mol of gas A and 3.84 mol of gas B, at a temperature of 32.0 °C.Calculate the partial pressure of each gas in the cylinder.Assume ideal gas behavior.

PA=____kPA        PB=____kPA

What is the total pressure?

PTotal=____kPA

Nov 2nd, 2014

To calculate the partial pressure of each gas:

Partial pressure  = (mol gas) * (R) * (Temp in K) / (volume in L)

PA = (1.18 mol)*(0.08206 Latm/molK)(305.15 K) / (6.62L) = 4.46 atm

PB = (3.84 mol)*(0.08206 Latm/molK)(305.15K) / (6.62 L) = 14.53 atm

Ptoal = PA + PB = 4.46 + 14.53 = 18.99 atm

Nov 2nd, 2014

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Nov 2nd, 2014
...
Nov 2nd, 2014
Dec 9th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer