Any help would be greatly appreciated.

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

A 6.62-L cylinder contains 1.18 mol of gas A and 3.84 mol of gas B, at a temperature of 32.0 °C.Calculate the partial pressure of each gas in the cylinder.Assume ideal gas behavior.

PA=____kPA        PB=____kPA

What is the total pressure?

PTotal=____kPA

Nov 2nd, 2014

To calculate the partial pressure of each gas:

Partial pressure  = (mol gas) * (R) * (Temp in K) / (volume in L)

PA = (1.18 mol)*(0.08206 Latm/molK)(305.15 K) / (6.62L) = 4.46 atm

PB = (3.84 mol)*(0.08206 Latm/molK)(305.15K) / (6.62 L) = 14.53 atm

Ptoal = PA + PB = 4.46 + 14.53 = 18.99 atm

Nov 2nd, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Nov 2nd, 2014
...
Nov 2nd, 2014
Oct 22nd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer