Solve the equation {x,x}

label Algebra
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schedule 1 Day
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Nov 4th, 2014

5x2+7x-4 =8x

5x2-x-4 =0

5x2-5x+4x-4 =0

5x(x-1)+4(x-1)=0

(5x+4)(x-1)=0

x=1 is admissible


Nov 4th, 2014

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