Here we have to use gas equation to calculate the number of moles of air in the flask.
Volume of flask =final weight - initial weight=299.4-56.53=242.87 gm =242.87 ml as water density is 1gm/ml
pressure =0.9315atm -water vapour pressure
Water vapour pressure = 50% of 21torr (as in this experiment RH is 50% and 21 torr is the saturation vapour pressure at 23 deg c)
So the pressure of air =0.9315-10.5/760(converted into atm)=0.9315-0.0138=.9177atm
pv=nrt i.e 0.9177x242.87/1000=nx.0821(valueof R)X296(TEMPIN KELVIN)
1.THIS GIVES N=0.009172 MOLES OF AIR
2.MASS OF AIR IN FLASK=0.009172X28.96=0.2656GM OF AIR
If we need to calculate mass of CO2 filled flask.
PRESSURE =0.9315ATM-21/760 ATM(VAPOUR PRESSURE OF WATER AT 100%RH=0.9039
USING GAS EQN
3.n=.009033moles of CO2=.009033X44(MOL WT OF CO2)=0.3975 GMOF CO2
4.IF FLASK IS FILLED WITH CO2 WITHOUT ANY WATER VAPOUR
THE GAS EQN TO BE USED IS
n works out to be 0.0093mass of CO2=0.0093X44=0.4096
Hence mass of flask plus stopper plus CO2=56.5=0.4096=56.9096GM
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