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Chemistry question .

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Oct 26th, 2014

Here we have to use gas equation to calculate the number of moles of air in the flask.

Volume of flask =final weight - initial weight=299.4-56.53=242.87 gm =242.87 ml as water density is 1gm/ml

pressure =0.9315atm -water vapour pressure

Water vapour pressure = 50% of 21torr (as in this experiment RH is 50% and 21 torr is the saturation vapour pressure at 23 deg c)

So the pressure of air =0.9315-10.5/760(converted into atm)=0.9315-0.0138=.9177atm

pv=nrt i.e 0.9177x242.87/1000=nx.0821(valueof R)X296(TEMPIN KELVIN)

1.THIS GIVES N=0.009172 MOLES OF AIR 

2.MASS OF AIR IN FLASK=0.009172X28.96=0.2656GM OF AIR

If we need to calculate mass of CO2 filled flask.

PRESSURE =0.9315ATM-21/760 ATM(VAPOUR PRESSURE OF WATER AT 100%RH=0.9039

USING GAS EQN

0.9039X242.87/1000=nx0.0821x296

3.n=.009033moles of CO2=.009033X44(MOL WT OF CO2)=0.3975 GMOF CO2

4.IF FLASK IS FILLED WITH CO2 WITHOUT ANY WATER VAPOUR

THE GAS EQN TO BE USED IS

0.9315X242.87/1000=nx0.0821x296

n works out to be 0.0093mass of CO2=0.0093X44=0.4096

Hence mass of flask plus stopper plus CO2=56.5=0.4096=56.9096GM

Nov 5th, 2014

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Oct 26th, 2014
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Oct 26th, 2014
Jun 26th, 2017
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