Algebra - 2-3 paper on Real World Radical Formulas

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Real World Radical Formulas

Read the following instructions to complete this assignment:

  1. Solve parts a, b, and c of problem 103 on page 605 of Elementary and Intermediate Algebra.  I have attached the problem  Dugo.Chapter9.zip  
  2. Write a two- to three-page paper (not including the title page) that is formatted in APA style and according to the Math Writing Guide. Format your math work as shown in the example MAT222.W3.AssignmentExample.pdf  and be concise in your reasoning. In the body of your essay, do the following:

    • Explain what each of the three variables represents in problem 103. Study the Instructor Guidance examples to learn how to solve the formula for another variable.
    • Demonstrate your solution to all three parts of the problem, making sure to include all mathematical work and an explanation for each step.
    • Explain why the use of this equation is important for shipbuilders.
  3. Incorporate the following math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing your math work.):
    • Radical
    • Root
    • Variable
For information regarding APA samples and tutorials,

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Running head: RADICAL FORMULAS 1 Running header should use a shortened version of the title if the title is long. Page number is located at right margin. (full title; centered horizontally & vertically) Real World Radical Formulas John Q. Student MAT 222 Week 3 Assignment Instructor’s Name Date RADICAL FORMULAS 2 Real World Radical Formulas (title required on first line) Though radicals seem complicated at first glance, the concept simply extends what is already known about exponents and the order of operations. Additionally, manipulating formulas that include radicals is no different than those without, providing appropriate rules are followed. These rules include accurately finding the cube and square root for numbers and understanding the application of the solution in the real world. It is stated in #103 on page 605 (Dugopolski, 2012) that the capsize screening value C should be less than 2 if a boat is to be considered safe for ocean sailing. The formula is given as C = 4d-1/3b where d is the displacement in pounds and b is the beam width in feet. The exponent of -1/3 means that the cube root of d will be taken and then the reciprocal of that number will be used in the multiplication. a) For the first example, a 1963 Cascade 29 sailboat’s capsize screening value will be calculated. The boat has a beam of 8 ft 2 in. and a displacement of 8500 lbs. The inches value will be converted into a decimal by division (2/12). C = 4d-1/3b C = 4(8500)-1/3(8.17) Here are the values plugged into the formula. According to order of operations, the exponents are solved first (exponent computed by calculator). C = 4(.049)(8.17) Now it is just two multiplications. C = .196(8.17) C = 1.60 The capsize screening value is less than 2. b) Here is a formula similar to the capsize screening value. D = 1.1g -1/4H. The formula will be solved for g. D = 1.1g -1/4H No substitution is needed because the formula is being manipulated. RADICAL FORMULAS 3 D = 1.1g-1/4H 1.1H 1.1H Divide both sides by 1.1H. D-4 Raise all parts of both sides to the -4th power . The (1.1H)-4 = ( g-1/4)-4 (1.1H) -4 on the left side becomes its reciprocal to the 4th power. The right side becomes simply g. 1.4641H4 = g D4 The formula has now been solved for g. Problem 104 on page 606 (Dugopolski, 2012) gives a formula for computing the sail power of a boat based on the area of the sail A in square feet, and the displacement of d pounds. The formula is S = 16Ad-2/3 where S stands for the sail area-displacement ratio. The -2/3 exponent on the d means first the cube root will be taken, then the result of that will be squared, and finally the last result will divide 16A (i.e. sent to the denominator). a) The boat has a sail area of 510 square feet and a displacement of 8500 lbs. S = 16Ad-2/3 S = 16(510)(8500)-2/3 Values plugged into the formula. Exponents are calculated first (exponent computed by calculator). S = 16(510)(.0024) Complete multiplication left to right. S = 8160(.0024) S = 19.584 This seems to be a good amount of sail power for this boat. It might be so high because the replaced original sail was only 405 square feet with a larger sail of 510 feet. b) Here is a formula similar to the sail area-displacement ratio: T = 8Bg -3/4 . Once again the formula will be solved for g. T = 8Bg -3/4 8B 8B Divide both sides by 8B. RADICAL FORMULAS 5 Now let us consider an analysis of the graph for the capsize screening value, C. C = 4d-1/3b. Since there are three variables this function actually represents a family of functions based on varying values for the boats beam, b. Say we want to look at the graphs for beams of 8, 10 and 12 feet. That means 3 functions, one for each value of b. C = 4d-1/3*8 = 32d-1/3 C = 4d-1/3*10 = 40d-1/3 C = 4d-1/3*12 = 48d-1/3 Here is the graph of the family of functions for b = 8 (purple), 10 (black) and 12 (red) foot beams. RADICAL FORMULAS Recall that the boat is less likely to capsize when the capsize screening factor, C, is less than 2. These graphs can now be used to determine the safe displacements given a particular beam. Note that a larger beam can carry a larger displacement and still remain safe. Conclusion paragraph would go here. Remember to include 2-3 sentences to make a complete paragraph. 5 RADICAL FORMULAS 5 Reference Dugopolski, M. (2012). Elementary and intermediate algebra (4th ed.). New York, NY: McGraw-Hill Publishing. Use the word ‘Reference’ or ‘References’ as the title. Text should ALWAYS be included in every assignment! Be sure to use appropriate indentation (hanging), font (Arial or Times New Roman), and size (12).
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