2 separated report for Circuit class, physics homework help

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nyny

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Hi,, I want somebody to write me a 2 seperated report for Circuit class, the report does not has to be long.

Experiments, some numbers, and what the report must include, are attached below.

Please write all numbers and calculations that needed or you got, I really need it.

Example of report is attached.

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EE210 Lab Experiment X 10 Introduction to Operational Amplifiers Objective: • Construct and verify the operation of an inverting operational amplifier circuit. Procedure: 1. Construct the circuit shown in Figure 1. You will need to use both adjustable supplies (set one to +15 V and the other to -15 V) and the fixed 5 V supply from the DC power supply. 2. Measure the output voltage of the amplifier for 4 different values of Rf (270 Ω, 1 kΩ, 2 kΩ, 5.1 kΩ). Calculate the voltage gain of the circuit (Av = vo/vi) for each resistance value. 3. Verify results from step 2 with an LTSpice simulation (use the LT1001 op amp). Rf Ri = 1 kΩ vi = 5V + 15V – vd + + vo − 15V − Figure 1 Discussion: Compare lab and simulation gain results with the theoretical gain assuming that the op amp is operating in the linear region. For what value(s) of Rf does the op amp go into saturation? EE210 Lab Experiment 11 XI The Noninverting Operational Amplifier Objective: • Construct and verify the operation of a noninverting operational amplifier circuit. • Be introduced to the Function Generator and the Oscilloscope. Procedure: 1. Construct the circuit shown in Figure 1. Use an Rf value of 5.1 kΩ. Use the function generator as the input voltage source vi. 2. Connect Channel 1 of the oscilloscope to the function generator. Connect Channel 2 of the oscilloscope of the op amp output. Use the same vertical scale for both oscilloscope channels. Adjust the function generator to produce a 1 V amplitude sine wave at a frequency of 1000 Hz. Sketch (as accurately as possible) the oscilloscope display showing both waveforms. Indicate the oscilloscope vertical and horizontal scale settings next to the sketch. 3. Repeat step 2 using with a triangular wave as the input signal. Rf Ri = 1 kΩ + 15V – vd + vi + vo − 15V Figure 1 − Lab Report (Word Processor)  Introduction - Identify Experiment - Objectives  Procedure - Summary of steps - Circuit Diagram (open and short circuits)  Results - Tables - Graphs - Text describing tables/graphs  Conclusions - Address objectives while referencing results Lab 10: Lab 11: Ri  R1k = 0.998 KΩ Sine wave: Rf  R5.1k= 5.04 kΩ Triangular wave: Name course This experience shows the difference between the series and parallel circuits and the distribution of current and voltage variation and the effect of resistance to them. Objective: - See which one will effect (current or voltage) in the series and parallel circuit. - To see the difference between the voltage division and current division. First we got three resistances and we measured them, so we can see the difference in different circuits. Using 12V supply we constructed the series circuit first, and we used the ohmmeter to measure the voltage for each resistor and the equivalent resistance for the whole circuit. Then we connect the same resistors in parallel. And we measured the currents for each resistor, and we got the equivalent resistance at the end. Finally, we compared the results with the theoretical one using the voltage division for series circuit and the current division for parallel circuit. Diagrams: Resistance in Series: R1= 0.988 , R2= 1.958 , R3= 2.973. , V3= 6.03V R(eq)= 0.988 + 1.958 + 2.973 = 5.919. V1= 1.99V , V2= 3.97V Theoretical V1, V2, V3 using voltage division formula: V = 12V V1= (R1/R(eq))(V) = (0.988/5.919)(12) = 2.00V V2= (R2/R(eq))(V) = (1.958/5.919)(12) = 3.96V V3= (R3/R(eq))(V) = (2.973/5.919)(12) = 6.02V Resistance in Parallel: R1= 0.988 , R2= 1.958 , R3= 2.973. R(eq)= 0.535. Theoretical R(eq): 0.988||1.958 = (0.988*1.958)/(0.988+1.958)=0.65665. 0.65665||2.973 = (0.65665*2.973)/( 0.65665+2.973)=0.537. I1= 12.11A , I2= 6.08A , I3= 4.03A Theoretical I1, I2, I3: I1= V/R1 = 12*0.988 = 12.145A I2= V/R2 = 12*1.958 = 6.128A I3= V/R3 = 12*2.973 = 4.036A Current from power supply = 22.24A Theoretical Current from power supply  I= V/R(eq)=12/0.537=22.34A That actually verify Ohm’s Law which from we got the current and voltage divisions. On the series circuit we got the same current for all resistors and voltage are varies. On the other hand, in parallel circuit we got the same voltage for all resistors but the currents were varying.
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Non inverting amplifier

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Introduction
We have studied that operational amplifiers are linear devices that are used for
amplification in an electric circuit for signal conditioning, filtering, or performing
mathematical operations. The operational amplifier amplifiers a signal by amplifying
the voltage input. The operational amplifier are normally used with feedback
components such as resistors and capacitors between its input and output. It is
characterized by high input impedance, high open loop gain, and low output impedance.
Figure 1 is an example of an Op-Amp. It contains two inputs the inverting input and
th...


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