Please Help Routing Question

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An IPS router is advertising a summarized address of 192.0.0.0/8. How many network addresses is this router is advertising? Support your answer with calculations. 

Nov 7th, 2014

The "Eight" in the specification of CIDR 192.0.0.0/8 is showing the fixed state of top eight bits. Every one of the four octets is 8 bits, so 8 bits fixed shows that the first octet (192) is fixed.
This makes simpler computation, as the remaining 3 octets each represent 1 byte = 8 bits. Each octet can be presented as 256 exclusive addresses, so we have 3 existing octets and that is 256 x 256 x 256 = 16,777,216 addresses of network. 

     Performing the dilemma in alternate way, the lowest 24 bits are not fixed and are consequently accessible for addressing. Then we have 224 = 16,777,216 addresses of network.

Nov 7th, 2014

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Nov 7th, 2014
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