3log base 2 of (x-1) log base 2 of 4 = 5

Mathematics
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Totally stumped. Tried it several different ways. Can not find a way to solve for x, and I know I am just missing something.

Nov 8th, 2014

3logbase2(x-1) + log base2 4 = 5

2log base2(x-1) +logbase2(x-1) + log base2 4 = 5

by loga + logb = log(a*b)

2 logbase2 (x-1) + logbse2 (x-1)*4 =5

logbase2 (x-1)^3 *4 = 5

(x-1)^3 = 2^3

x-1 = 2

x = 3 

please best my answer

Nov 8th, 2014

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