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You need to find the least common multiple of 6 oz (pineapple juice) and 10 oz (orange juice). The least common multiple of 6 and 10 is 30 (6x5 = 30 and 10 x 3 = 30). You need 5 x 6 oz cans of pineapple juice and 3 x 10 oz cans of orange juice.
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Problems dealing with Confidence Interval Estimation and Hypothesis Testing
There are actually 9 problems broken down to individual components to identify key steps required to solve the problem. Th ...
Problems dealing with Confidence Interval Estimation and Hypothesis Testing
There are actually 9 problems broken down to individual components to identify key steps required to solve the problem. They appear as multiple chioce questions. For example the 1st 8 questions are dealing with one problem.The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. A random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating a 95% confidence interval estimate of the average number of days absent for the company's workers last year what will be the standard error?4.0.16.80.0251.8 points QUESTION 2The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating a 95% confidence interval estimate of the average number of days absent for the company's workers last year should you use a z or t value in the formula?zt1.8 points QUESTION 3The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating a 95% confidence interval estimate of the average number of days absent for the company's workers last year what would be the value of your UPPER limit?17.9610.0311.358.0491.8 points QUESTION 4The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year what is the sample proportion used in the formula?.12.10.480401.9 points QUESTION 5The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year would you use a z or t in the formula?zt1.9 points QUESTION 6The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year what is the value of the Z used in the formula?1.7081.7111.651.961.9 points QUESTION 7The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year what is the upper limit of the confidence interval?.516.6445.284.6761.9 points QUESTION 8You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. Is this a 1 or 2 tail test?1 tail2 tailindeterminatenone of the above1 points QUESTION 9You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. What are your critical values?+- 1.65+- 2.045+-1.96+-1.651.8 points QUESTION 10You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. What is the value of your test statistic?.30-.308.98-1.641.9 points QUESTION 11You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. If your test statistic is -1.64 what will be your decision?Reject HoReject H1Do not reject H1Do not reject Ho1.9 points QUESTION 12You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. What is your conclusion?There is evidence of a difference in the average return.There is no evidecne of a difference in the average returnIndeterminateInconclusive1.9 points QUESTION 13A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a 1 or 2 tail test?1 tail2 tail1.9 points QUESTION 14A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a one sample or two sample test?one sampletwo sample1.9 points QUESTION 15A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a test of sample means or sample proportions?sample proportionssample meansbothneither1 points QUESTION 16A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What are your critical values?+- 1.65+-1.961.741.791.9 points QUESTION 17A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What is the value of your pooled proportion?.27.73.55.051.9 points QUESTION 18A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What is the value of your test statistic?1.961.651.74.051.9 points QUESTION 19A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What is your decision?Reject HoReject H1Do not reject Honone of the above1.9 points QUESTION 20A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. If you determine not to reject the null hypothesis what is your conclusion?There is evidence of a difference in the proportions of college aged students and non college aged students having accidentsThere is no evidence of a difference in the proportions of college aged students and non college aged students having accidentsthe data is inconclusivenone of the above1.9 points QUESTION 21A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. Is this a 1 or 2 tail test?1 tail2 tail1.9 points QUESTION 22A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is the H1?H1: U< 90H1 not equal to 90H1: U>90Ho: U > or equal to 901.9 points QUESTION 23A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. Is this a Z or t test?tZ1.9 points QUESTION 24A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. Assuming we are using a t test what will be the critical value"?1.28-1.281.29-1.291.9 points QUESTION 25A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is the value of your test statistic?1.281.791.82-1.821.9 points QUESTION 26A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is your decision?reject Hodo not reject Horeject H1none of the above1.9 points QUESTION 27A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is your conclusion?there is no evidence that there has been an increase in the average selling timethere is evidence that there has been an increase in the average selling timethere is no evidence that there has been a decrease in the average selling timethere is evidence that there has been a decrease increase in the average selling time1.9 points QUESTION 28The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. Is this a one or two tail test?1 tail2 tailbothneither1.9 points QUESTION 29The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. Is this a Z, t, or F test?ZtF1.9 points QUESTION 30The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is the alternate hypothesis?Ho: proportion > .55H1: proportion > .55H1: proportion < .55H1: proportion > .601.9 points QUESTION 31The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is the value of your critical value?1.96-1.961.645-1.6451.9 points QUESTION 32The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is the value of your test statistic?.60.85.05.551.9 points QUESTION 33The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is your decision?reject H1do not reject Horeject Hoindeterminate1.9 points QUESTION 34The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is your conclusion?There is evidence that more than 55% would use the route and therefore the STA criteria is met.There is no evidence that more than 55% would use the route and therefore the STA criteria was not met..60 is greater than .55 so the criteria is metindeterminant1.9 points QUESTION 35An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. Is this a one sample test or a two sample test?one sample testtwo sample testneitherboth1.9 points QUESTION 36An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. Is this a one tail or two tail test?neitherone tailtwo tail1.5 points QUESTION 37An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is H1?Ua < Um where "m" is morning and "a" is afternoonUm > UaUa > UmUa not equal to Um1.9 points QUESTION 38An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is your critical value?1.961.281.645.051.9 points QUESTION 39An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is your test statistic?1.6451.28.0561.9 points QUESTION 40An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. If your critical value is on the right of your curve and your test statistic is less than the critical value what will be your decision?reject H1do not reject Horeject Hoit depends1.9 points QUESTION 41An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is your conclusion?There is evidence that the mean number of units produced by the afternoon shift is larger.There is evidence that the mean number of units produced by the morning shift is larger.There is no evidence that the mean number of units produced by the afternoon shift is larger.There is evidence that the mean number of units produced by the morning shift is smaller.1.9 points QUESTION 42The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is the alternate hypothesisUe < Ub where e =end of month and b=begining of monthUe > UbUb > UeUb = Ue1.9 points QUESTION 43The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is your critical value?1.7010.501.6451.961.9 points QUESTION 44The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is the value of your test statistic?-2.0311.752.03-11.051.9 points QUESTION 45The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is your decision?reject Hodo not reject Hoindeterminatereject H11.9 points QUESTION 46The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is your conclusion?There is no evidence of a difference in the mean weightthere is no evidence that the packages shipped at the end of the month weigh morethere is evidence that the packages shipped at the end of the month weigh morethere is evidence that the packages shipped at the end of the month weigh less1.9 points QUESTION 47A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is the alternate hypothesis?Uf does not equal Um, where f=final and m=midtermUf < UmUm > UfUf > Um1.9 points QUESTION 48A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is the critical value?1.963.52.283.14271.9 points QUESTION 49A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is your test statistic?10.579.273.5041.961.9 points QUESTION 50A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is your decision?do not reject Horeject Horeject H1inconclusive1.9 points QUESTION 51A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is your conclusion?There is no difference between the scoresthere is no evidence of a significant improvement on the finalthere is evidence of a significant improvement on the finalstudents scored better on the midterm1.9 points QUESTION 52There are two car dealerships in a particular area. The mean monthly sales at the two dealerships are about the same. However, one of the dealerships (dealership A) is boasting to corporate headquarters that his dealership’s monthly sales are more consistent. An industry analyst reviews the last seven months at dealership A and finds the standard deviation of the seven monthly sales to be 14.79. He reviews the last eight months at dealership B and finds the standard deviation of the eight monthly sales to be 22.95. Using the .01 significance level you will test to conclude if the analyst finds evidence that the boast of dealership A is correct. What will be your critical value?1.1.552.1.353.2.414.8.261.9 points QUESTION 53There are two car dealerships in a particular area. The mean monthly sales at the two dealerships are about the same. However, one of the dealerships (dealership A) is boasting to corporate headquarters that his dealership’s monthly sales are more consistent. An industry analyst reviews the last seven months at dealership A and finds the standard deviation of the seven monthly sales to be 14.79. He reviews the last eight months at dealership B and finds the standard deviation of the eight monthly sales to be 22.95. Using the .01 significance level you will test to see if the analyst finds evidence that the boast of dealership A is correct. What is the value of the test statistic?2.418.261.551.961.9 points QUESTION 54There are two car dealerships in a particular area. The mean monthly sales at the two dealerships are about the same. However, one of the dealerships (dealership A) is boasting to corporate headquarters that his dealership’s monthly sales are more consistent. An industry analyst reviews the last seven months at dealership A and finds the standard deviation of the seven monthly sales to be 14.79. He reviews the last eight months at dealership B and finds the standard deviation of the eight monthly sales to be 22.95. Using the .01 significance level does the analyst find evidence that the boast of dealership A is correct?yesnoindeterminant
Statistics problems
Here is a list of the problems. Answers need to be provided in the attached Word document.
1.The
singular form of the wo ...
Statistics problems
Here is a list of the problems. Answers need to be provided in the attached Word document.
1.The
singular form of the word “dice” is “die”. Tom was throwing a six-sided die.
The first time he threw, he got a three; the second time he threw, he got a
three again. What’s the probability of getting a three at the third time? 2.There are 30 table tennis balls in the box: 6
are green, 10 are red, and 14 are yellow. If you shake the box and then
randomly select one ball from the box, what’s the probability that you will get
a red one: 3. Rachel was flipping a coin with Jerry. She
told jerry: “I am able to get all heads in two tosses.” Jerry laughed at her:
“No, the probability of getting two heads at two tosses is only__” 4. Jennie and Alex both wanted to get a free
ticket for a College Music concert. However, the concert staff told them the
tickets were limited. Twenty people wanted to attend the concert but only 10
free tickets were left. So the concert center staff decided to use a lottery to
decide who would receive the free tickets. What’s the probability of Jennie and
Alex both getting free tickets? 5.Laura and Melissa were playing dice. What the probability of Laura and
Melissa both getting a 6? 6. In a statistics class with 36 students, the
professor wanted to know the probability that at least two students share the
same birthday. The probability will be___ a. 0.1 b. Much
smaller than 0.1 c. Much
bigger than 0.1 d. Not
possible 7. If you throw a die for two times, what is the
probability that you will get a one on the first throw or a one on the second
throw (or both)? 8. Jerry got a box full of colorful candy balls.
There were 50 of them: 20 red, 10 green, 12 yellow and 8 blue. After shaking
the box, he randomly selected 2 candy balls from the box. What’s the
probability that the first one was blue and the second one was yellow? 9.Jerry got a box full of colorful candy balls. There were 50 of them: 20
red, 10 green, 12 yellow and 8 blue. After shaking the box, he randomly
selected 2 candy balls from the box. What’s the probability that the first is
blue and the second one is also blue? 10. Which activity could probabilities be computed using a Binomial
Distribution? a. Flipping a
coin a 100 times b. Throwing a
die one hundred times c. The
probability of getting a heart while playing card games d. Grades
earned by 100 students on a statistics final exam 11. Many researchers have argued that
the TB skin test is not accurate. Imagine that the TB skin test is only 70%
accurate. Sarah is thinking about having the test. Before she has the test she
wonders the probability that she has TB. The probability of Sarah having TB is
… a. 70% b. 35% c. 30% d. More information needed to calculate 12. Imagine that the diabetic test
accurately indicates the disease in 95% of the people who have it. What’s the
miss rate? 13. Which of the following is the probability that subjects do not have
the disease, but the test result is positive? a. Miss rate b. False
positive rate c. Base rate d. Disease
rate 14. In a normal distribution, the median is ____it’s mean and
mode. a. Approximately
equal to b. Bigger
than c. Smaller
than d. Unrelated
to 15. In a normal distribution, __ percentage of the area under
the curve is within one standard deviations of the mean? a. 68% b. 100% c. 95% d. It
depends on the values of the mean and standard deviation 16. A normal distribution with a mean of 15 and standard
deviation of 5. 95% of its area is within__ a. One
standard deviation of the mean b. Two
standard deviations of the mean c. Three
standard deviations of the mean d. It
depends on the value of the mode 17.The mean of a standard normal
distribution is: a. 0 b. 1.0 c. -1.0 d. 100 18. The standard deviation of the mean for a standard
distribution is: a. 0.0 b. 1.0 c. 100 d. 68% 19. A normal distribution with a mean
of 25 and standard deviation of 5. What is the corresponding Z score for a case
having a value of 10? 20. Consider
a normal distribution with a mean of 25 and standard deviation of 4.
Approximately, what proportion of the area lies between values of 17 and 33. a. 95% b. 68% c. 99% d. 50% 21. Consider a normal distribution
with a mean of 10 and standard deviation of 25. What’s the Z score for the
value of 35? 22. For a standard normal distribution, what’s the probability
of getting a positive number? a. 50% b. 95% c. 68% d. We
cannot tell from the given information 23.Two-hundred students took a
statistics class. Their professor creatively decided to give each of them their
Z-score instead of their grade. Rachel got her Z-score of -0.2. She was
wondering how well she did on the exam. a. It
was very good, much better than almost all of the other students b. It
was so-so, but still better than half of the students. c. It
was not that good, but not at the bottom of the distribution d. It
was very bad and she needs to work much harder next time 24. A researcher collected some data and they form a normal
distribution with a mean of zero. What’s the probability of getting a positive
number from this distribution? a. 25% b. 50% c. 75% d. We
need to calculate the standard deviation and then decide. 25. Which of the following description of distribution is
correct? a. A
Binomial distribution is a probability distribution for independent events for
which there are only two possible outcomes b. You
cannot use the normal distribution to approximate the binomial distribution c. Normal
distributions cannot differ in their means and in their standard deviations. d. Standard
normal distributions can differ in their means and in their standard
deviations. 26. A toy factory makes 5,000 teddy
bears per day. The supervisor randomly selects 10 teddy bears from all 5,000
teddy bears and uses this sample to estimate the mean weight of teddy bears and
the sample standard deviation. How many degrees of freedom are there in the
estimate of the standard deviation? 27. Imagine you have a population of 100,000 cases. For which of
the following degrees of freedom is the closest estimation of the population
parameter? a. 4 b. 6 c. 10 d. 1000 28.Imagine that the average weight of a
total of 500 girls in a high school is 35kg. Tom randomly sampled 10 girls and
measured their weight. And then he repeated this procedure for three times. The
means and standard deviations are listed as following. Which sample estimate
shows the least sample variability? a. Sample
one: mean=34, SE=5 b. Sample
two: mean=30, SE=2 c. Sample
three: mean= 26, SE=3 d. Sample
four: mean= 38, SE=5 29. For which of the following degrees of freedom is a t
distribution closest to a normal distribution? a. 10 b. 20 c. 5 d. 1000 30. In order to construct a confidence interval for the
difference between two means, we are going to assume which of the followings?
(Select all that apply) a. The
two populations have the same variance. b. The
populations are normally distributed. c. Each
value is sampled independently from each other value. d. The
two populations have similar means 31. A researcher tries to compare
grades earned on the first quiz by boys and girls. He randomly chooses 10
students from boys and 15 students from girls and calculates the confidence
interval on difference between means. How many degrees of freedom will you get
in this t distribution? 32. Which of the following choices is not the possible
confidence interval on the population values of a Pearson’s correlation? a. (0.3,
0.5) b. (-0.7,
0.9) c. (-1.2,
0.3) d. (0.6,
0.8)33. Which of the following descriptions
of the t distribution is correct? (Select all that apply) a. With
smaller sample sizes, the t distribution is leptokurtic b. When
the sample size is large (more than 100), the t distribution is very similar to
the standard normal distribution c. With
larger sample sizes, the t distribution is leptokurtic d. The
t distribution will never be close to normal distribution 34. _________________refers to whether or not an estimator tends
to overestimate or underestimate a parameter. ______________ is the standard
deviation of the sampling distribution and play a critical role in the
constructing confidence intervals and in significance testing.a. Bias;
standard error b. Sample
population; Bias c. Mean;
standard deviation d. Standard
deviation; Mean 35. Which of the following descriptions of confidence intervals
is correct? a. Confidence
intervals can only be computed for the mean b. We
can only use the normal distribution to compute confidence intervals c. Confidence
intervals can be computed for various parameters d. Confidence
intervals can only be computed for the population
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There are actually 9 problems broken down to individual components to identify key steps required to solve the problem. They appear as multiple chioce questions. For example the 1st 8 questions are dealing with one problem.The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. A random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating a 95% confidence interval estimate of the average number of days absent for the company's workers last year what will be the standard error?4.0.16.80.0251.8 points QUESTION 2The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating a 95% confidence interval estimate of the average number of days absent for the company's workers last year should you use a z or t value in the formula?zt1.8 points QUESTION 3The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating a 95% confidence interval estimate of the average number of days absent for the company's workers last year what would be the value of your UPPER limit?17.9610.0311.358.0491.8 points QUESTION 4The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year what is the sample proportion used in the formula?.12.10.480401.9 points QUESTION 5The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year would you use a z or t in the formula?zt1.9 points QUESTION 6The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year what is the value of the Z used in the formula?1.7081.7111.651.961.9 points QUESTION 7The labor relations manager of a large corporation wished to study the absenteeism among workers at the company's central office during the last year. a random sample of 25 workers revealed the following: an average of 9.7 days; a standard deviation of 4.0 days; and 12 employees were absent more than 10 days. In estimating the 95% confidence interval estimate of the proportion of workers absent more than 10 days last year what is the upper limit of the confidence interval?.516.6445.284.6761.9 points QUESTION 8You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. Is this a 1 or 2 tail test?1 tail2 tailindeterminatenone of the above1 points QUESTION 9You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. What are your critical values?+- 1.65+- 2.045+-1.96+-1.651.8 points QUESTION 10You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. What is the value of your test statistic?.30-.308.98-1.641.9 points QUESTION 11You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. If your test statistic is -1.64 what will be your decision?Reject HoReject H1Do not reject H1Do not reject Ho1.9 points QUESTION 12You are considering investing in a company. The company claims for the past few years the average monthly return on such an investment has been $870 with a standard deviation of $50. You sample 30 investors and determine the sample average return to be $855. Using a .05 level of significance you will test to determine if there is evidence that the true average return is different from $870. What is your conclusion?There is evidence of a difference in the average return.There is no evidecne of a difference in the average returnIndeterminateInconclusive1.9 points QUESTION 13A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a 1 or 2 tail test?1 tail2 tail1.9 points QUESTION 14A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a one sample or two sample test?one sampletwo sample1.9 points QUESTION 15A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a test of sample means or sample proportions?sample proportionssample meansbothneither1 points QUESTION 16A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What are your critical values?+- 1.65+-1.961.741.791.9 points QUESTION 17A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What is the value of your pooled proportion?.27.73.55.051.9 points QUESTION 18A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What is the value of your test statistic?1.961.651.74.051.9 points QUESTION 19A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. What is your decision?Reject HoReject H1Do not reject Honone of the above1.9 points QUESTION 20A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. If you determine not to reject the null hypothesis what is your conclusion?There is evidence of a difference in the proportions of college aged students and non college aged students having accidentsThere is no evidence of a difference in the proportions of college aged students and non college aged students having accidentsthe data is inconclusivenone of the above1.9 points QUESTION 21A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. Is this a 1 or 2 tail test?1 tail2 tail1.9 points QUESTION 22A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is the H1?H1: U< 90H1 not equal to 90H1: U>90Ho: U > or equal to 901.9 points QUESTION 23A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. Is this a Z or t test?tZ1.9 points QUESTION 24A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. Assuming we are using a t test what will be the critical value"?1.28-1.281.29-1.291.9 points QUESTION 25A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is the value of your test statistic?1.281.791.82-1.821.9 points QUESTION 26A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is your decision?reject Hodo not reject Horeject H1none of the above1.9 points QUESTION 27A statewide real estate company specializes in selling farm property in the state of Nebraska. Their records indicate that the mean selling time of farm property is 90 days. Because of recent drought conditions, they believe that the mean selling time is now greater than 90 days. A statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. At the .10 significance level you will test to determine if there has been an increase in selling time. What is your conclusion?there is no evidence that there has been an increase in the average selling timethere is evidence that there has been an increase in the average selling timethere is no evidence that there has been a decrease in the average selling timethere is evidence that there has been a decrease increase in the average selling time1.9 points QUESTION 28The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. Is this a one or two tail test?1 tail2 tailbothneither1.9 points QUESTION 29The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. Is this a Z, t, or F test?ZtF1.9 points QUESTION 30The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is the alternate hypothesis?Ho: proportion > .55H1: proportion > .55H1: proportion < .55H1: proportion > .601.9 points QUESTION 31The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is the value of your critical value?1.96-1.961.645-1.6451.9 points QUESTION 32The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is the value of your test statistic?.60.85.05.551.9 points QUESTION 33The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is your decision?reject H1do not reject Horeject Hoindeterminate1.9 points QUESTION 34The policy of the Suburban Transit authority is to add a bus route if more than 55 percent of the potential commuters indicate they would use the particular route. A sample of 70 commuters revealed that 42 would use a proposed route from Bowman Park to the downtown area. You will be testing to determine if the Bowman-to-downtown route meets the STA criterion using the .05 significance level. What is your conclusion?There is evidence that more than 55% would use the route and therefore the STA criteria is met.There is no evidence that more than 55% would use the route and therefore the STA criteria was not met..60 is greater than .55 so the criteria is metindeterminant1.9 points QUESTION 35An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. Is this a one sample test or a two sample test?one sample testtwo sample testneitherboth1.9 points QUESTION 36An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. Is this a one tail or two tail test?neitherone tailtwo tail1.5 points QUESTION 37An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is H1?Ua < Um where "m" is morning and "a" is afternoonUm > UaUa > UmUa not equal to Um1.9 points QUESTION 38An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is your critical value?1.961.281.645.051.9 points QUESTION 39An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is your test statistic?1.6451.28.0561.9 points QUESTION 40An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. If your critical value is on the right of your curve and your test statistic is less than the critical value what will be your decision?reject H1do not reject Horeject Hoit depends1.9 points QUESTION 41An industrial engineer would like to determine whether there are more units produced on the afternoon shift than on the morning shift. A sample of 50 morning-shift workers showed that the mean number of units produced was 345, with a standard deviation of 21. A sample of 60 afternoon-shift workers showed the mean number of units produced was 351, with a standard deviation of 28 units. At the .05 significance level we will test if the mean number of units produced on the afternoon-shift is larger. What is your conclusion?There is evidence that the mean number of units produced by the afternoon shift is larger.There is evidence that the mean number of units produced by the morning shift is larger.There is no evidence that the mean number of units produced by the afternoon shift is larger.There is evidence that the mean number of units produced by the morning shift is smaller.1.9 points QUESTION 42The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is the alternate hypothesisUe < Ub where e =end of month and b=begining of monthUe > UbUb > UeUb = Ue1.9 points QUESTION 43The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is your critical value?1.7010.501.6451.961.9 points QUESTION 44The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is the value of your test statistic?-2.0311.752.03-11.051.9 points QUESTION 45The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is your decision?reject Hodo not reject Hoindeterminatereject H11.9 points QUESTION 46The manager of a package courier service believes that packages shipped at the end of the month are heavier than those shipped early in the month. As an experiment, he weighed a random sample of 20 packages at the beginning of the month. He found that the mean weight was 20.25 pounds and the standard deviation was 5.84 pounds. Ten packages randomly selected at the end of the month had a mean weight of 24.80 pounds and a standard deviation of 5.67 pounds. At the .05 significance level, we will test to see if we can we conclude that the packages shipped at the end of the month weigh more. What is your conclusion?There is no evidence of a difference in the mean weightthere is no evidence that the packages shipped at the end of the month weigh morethere is evidence that the packages shipped at the end of the month weigh morethere is evidence that the packages shipped at the end of the month weigh less1.9 points QUESTION 47A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is the alternate hypothesis?Uf does not equal Um, where f=final and m=midtermUf < UmUm > UfUf > Um1.9 points QUESTION 48A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is the critical value?1.963.52.283.14271.9 points QUESTION 49A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is your test statistic?10.579.273.5041.961.9 points QUESTION 50A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is your decision?do not reject Horeject Horeject H1inconclusive1.9 points QUESTION 51A statistics professor would like to determine whether students in the class showed improved performance on the final exam as compared to the midterm examination. A random sample of 7 students selected from a large class revealed the following scores: midterm 70, 62, 57, 68, 89, 63, 82 and on the final 80, 79, 87, 88, 85, 79, 91. We will test to determine if there evidence of an improvement on the final examination, at the 1% significance level. What is your conclusion?There is no difference between the scoresthere is no evidence of a significant improvement on the finalthere is evidence of a significant improvement on the finalstudents scored better on the midterm1.9 points QUESTION 52There are two car dealerships in a particular area. The mean monthly sales at the two dealerships are about the same. However, one of the dealerships (dealership A) is boasting to corporate headquarters that his dealership’s monthly sales are more consistent. An industry analyst reviews the last seven months at dealership A and finds the standard deviation of the seven monthly sales to be 14.79. He reviews the last eight months at dealership B and finds the standard deviation of the eight monthly sales to be 22.95. Using the .01 significance level you will test to conclude if the analyst finds evidence that the boast of dealership A is correct. What will be your critical value?1.1.552.1.353.2.414.8.261.9 points QUESTION 53There are two car dealerships in a particular area. The mean monthly sales at the two dealerships are about the same. However, one of the dealerships (dealership A) is boasting to corporate headquarters that his dealership’s monthly sales are more consistent. An industry analyst reviews the last seven months at dealership A and finds the standard deviation of the seven monthly sales to be 14.79. He reviews the last eight months at dealership B and finds the standard deviation of the eight monthly sales to be 22.95. Using the .01 significance level you will test to see if the analyst finds evidence that the boast of dealership A is correct. What is the value of the test statistic?2.418.261.551.961.9 points QUESTION 54There are two car dealerships in a particular area. The mean monthly sales at the two dealerships are about the same. However, one of the dealerships (dealership A) is boasting to corporate headquarters that his dealership’s monthly sales are more consistent. An industry analyst reviews the last seven months at dealership A and finds the standard deviation of the seven monthly sales to be 14.79. He reviews the last eight months at dealership B and finds the standard deviation of the eight monthly sales to be 22.95. Using the .01 significance level does the analyst find evidence that the boast of dealership A is correct?yesnoindeterminant
Statistics problems
Here is a list of the problems. Answers need to be provided in the attached Word document.
1.The
singular form of the wo ...
Statistics problems
Here is a list of the problems. Answers need to be provided in the attached Word document.
1.The
singular form of the word “dice” is “die”. Tom was throwing a six-sided die.
The first time he threw, he got a three; the second time he threw, he got a
three again. What’s the probability of getting a three at the third time? 2.There are 30 table tennis balls in the box: 6
are green, 10 are red, and 14 are yellow. If you shake the box and then
randomly select one ball from the box, what’s the probability that you will get
a red one: 3. Rachel was flipping a coin with Jerry. She
told jerry: “I am able to get all heads in two tosses.” Jerry laughed at her:
“No, the probability of getting two heads at two tosses is only__” 4. Jennie and Alex both wanted to get a free
ticket for a College Music concert. However, the concert staff told them the
tickets were limited. Twenty people wanted to attend the concert but only 10
free tickets were left. So the concert center staff decided to use a lottery to
decide who would receive the free tickets. What’s the probability of Jennie and
Alex both getting free tickets? 5.Laura and Melissa were playing dice. What the probability of Laura and
Melissa both getting a 6? 6. In a statistics class with 36 students, the
professor wanted to know the probability that at least two students share the
same birthday. The probability will be___ a. 0.1 b. Much
smaller than 0.1 c. Much
bigger than 0.1 d. Not
possible 7. If you throw a die for two times, what is the
probability that you will get a one on the first throw or a one on the second
throw (or both)? 8. Jerry got a box full of colorful candy balls.
There were 50 of them: 20 red, 10 green, 12 yellow and 8 blue. After shaking
the box, he randomly selected 2 candy balls from the box. What’s the
probability that the first one was blue and the second one was yellow? 9.Jerry got a box full of colorful candy balls. There were 50 of them: 20
red, 10 green, 12 yellow and 8 blue. After shaking the box, he randomly
selected 2 candy balls from the box. What’s the probability that the first is
blue and the second one is also blue? 10. Which activity could probabilities be computed using a Binomial
Distribution? a. Flipping a
coin a 100 times b. Throwing a
die one hundred times c. The
probability of getting a heart while playing card games d. Grades
earned by 100 students on a statistics final exam 11. Many researchers have argued that
the TB skin test is not accurate. Imagine that the TB skin test is only 70%
accurate. Sarah is thinking about having the test. Before she has the test she
wonders the probability that she has TB. The probability of Sarah having TB is
… a. 70% b. 35% c. 30% d. More information needed to calculate 12. Imagine that the diabetic test
accurately indicates the disease in 95% of the people who have it. What’s the
miss rate? 13. Which of the following is the probability that subjects do not have
the disease, but the test result is positive? a. Miss rate b. False
positive rate c. Base rate d. Disease
rate 14. In a normal distribution, the median is ____it’s mean and
mode. a. Approximately
equal to b. Bigger
than c. Smaller
than d. Unrelated
to 15. In a normal distribution, __ percentage of the area under
the curve is within one standard deviations of the mean? a. 68% b. 100% c. 95% d. It
depends on the values of the mean and standard deviation 16. A normal distribution with a mean of 15 and standard
deviation of 5. 95% of its area is within__ a. One
standard deviation of the mean b. Two
standard deviations of the mean c. Three
standard deviations of the mean d. It
depends on the value of the mode 17.The mean of a standard normal
distribution is: a. 0 b. 1.0 c. -1.0 d. 100 18. The standard deviation of the mean for a standard
distribution is: a. 0.0 b. 1.0 c. 100 d. 68% 19. A normal distribution with a mean
of 25 and standard deviation of 5. What is the corresponding Z score for a case
having a value of 10? 20. Consider
a normal distribution with a mean of 25 and standard deviation of 4.
Approximately, what proportion of the area lies between values of 17 and 33. a. 95% b. 68% c. 99% d. 50% 21. Consider a normal distribution
with a mean of 10 and standard deviation of 25. What’s the Z score for the
value of 35? 22. For a standard normal distribution, what’s the probability
of getting a positive number? a. 50% b. 95% c. 68% d. We
cannot tell from the given information 23.Two-hundred students took a
statistics class. Their professor creatively decided to give each of them their
Z-score instead of their grade. Rachel got her Z-score of -0.2. She was
wondering how well she did on the exam. a. It
was very good, much better than almost all of the other students b. It
was so-so, but still better than half of the students. c. It
was not that good, but not at the bottom of the distribution d. It
was very bad and she needs to work much harder next time 24. A researcher collected some data and they form a normal
distribution with a mean of zero. What’s the probability of getting a positive
number from this distribution? a. 25% b. 50% c. 75% d. We
need to calculate the standard deviation and then decide. 25. Which of the following description of distribution is
correct? a. A
Binomial distribution is a probability distribution for independent events for
which there are only two possible outcomes b. You
cannot use the normal distribution to approximate the binomial distribution c. Normal
distributions cannot differ in their means and in their standard deviations. d. Standard
normal distributions can differ in their means and in their standard
deviations. 26. A toy factory makes 5,000 teddy
bears per day. The supervisor randomly selects 10 teddy bears from all 5,000
teddy bears and uses this sample to estimate the mean weight of teddy bears and
the sample standard deviation. How many degrees of freedom are there in the
estimate of the standard deviation? 27. Imagine you have a population of 100,000 cases. For which of
the following degrees of freedom is the closest estimation of the population
parameter? a. 4 b. 6 c. 10 d. 1000 28.Imagine that the average weight of a
total of 500 girls in a high school is 35kg. Tom randomly sampled 10 girls and
measured their weight. And then he repeated this procedure for three times. The
means and standard deviations are listed as following. Which sample estimate
shows the least sample variability? a. Sample
one: mean=34, SE=5 b. Sample
two: mean=30, SE=2 c. Sample
three: mean= 26, SE=3 d. Sample
four: mean= 38, SE=5 29. For which of the following degrees of freedom is a t
distribution closest to a normal distribution? a. 10 b. 20 c. 5 d. 1000 30. In order to construct a confidence interval for the
difference between two means, we are going to assume which of the followings?
(Select all that apply) a. The
two populations have the same variance. b. The
populations are normally distributed. c. Each
value is sampled independently from each other value. d. The
two populations have similar means 31. A researcher tries to compare
grades earned on the first quiz by boys and girls. He randomly chooses 10
students from boys and 15 students from girls and calculates the confidence
interval on difference between means. How many degrees of freedom will you get
in this t distribution? 32. Which of the following choices is not the possible
confidence interval on the population values of a Pearson’s correlation? a. (0.3,
0.5) b. (-0.7,
0.9) c. (-1.2,
0.3) d. (0.6,
0.8)33. Which of the following descriptions
of the t distribution is correct? (Select all that apply) a. With
smaller sample sizes, the t distribution is leptokurtic b. When
the sample size is large (more than 100), the t distribution is very similar to
the standard normal distribution c. With
larger sample sizes, the t distribution is leptokurtic d. The
t distribution will never be close to normal distribution 34. _________________refers to whether or not an estimator tends
to overestimate or underestimate a parameter. ______________ is the standard
deviation of the sampling distribution and play a critical role in the
constructing confidence intervals and in significance testing.a. Bias;
standard error b. Sample
population; Bias c. Mean;
standard deviation d. Standard
deviation; Mean 35. Which of the following descriptions of confidence intervals
is correct? a. Confidence
intervals can only be computed for the mean b. We
can only use the normal distribution to compute confidence intervals c. Confidence
intervals can be computed for various parameters d. Confidence
intervals can only be computed for the population
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