find the area of a circle inscribed in an equilateral triangle with sides of length 20 cm

If the side is 2 sqrt(3), then the radius is 1

Since side =20 radius = 20/(2*sqrt(3)) =10 *sqrt(3)/3

Area of the circle = pi* 10^2*3/9= pi*100/3 =3.14*100/3 =314/3 =104.67 sq cm

Reference:

http://www.algebra.com/algebra/homework/Surface-area.faq.question.485478.html

Answer: 100/3*pi or 104.67 sq cm

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