Evaluate tan^2 0 + cot^2 0 , given that sin 0 = 3/4

#please note where there is 0 its representing theta.

sin theta =3/4

cos theta^2 = 1-(3/4)^2= 1-9/16 =7/16

cos theta = sqrt(7)/4

tan theta = sin theta/cos theta = 3/sqrt(7)

tan theta^2 = 9/7

cot theta^2 = 7/9

tan theta ^2 +cot theta ^2 = 9/7+7/9 =(81+49)/63 =130/63 =2.063

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