‚ÄčA rectangle and a square both have the same area

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A rectangle and a square both have the same area 

Rectangle width =x+2 and length= 7x-10 
Square width= 3x-2 
Prove that x^2-8x+12=0
Nov 11th, 2014

here you go

Area_rectangle = (x+2)(7x-10) 
Area_square = (3x-2)^2 
as both areas are identical, we obtain: 
(x+2)(7x-10) = (3x-2)^2 
7x^2 + 4x - 20 = 9x^2 - 12x + 4 
fro right to left: 
2x^2 - 16x + 24 = 0 
finally : 
x^2-8x+12=0 

Good luck!

Nov 11th, 2014

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