A rectangle and a square both have the same area

here you go

Area_rectangle = (x+2)(7x-10) Area_square = (3x-2)^2 as both areas are identical, we obtain: (x+2)(7x-10) = (3x-2)^2 7x^2 + 4x - 20 = 9x^2 - 12x + 4 fro right to left: 2x^2 - 16x + 24 = 0 finally : x^2-8x+12=0

Good luck!

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up