Find the zeros of h(x)=x^2-x+2 by using the quadratic formula

the quadratic formula is [-b +- sqrt(b2-4ac)]/2a

in this case, a=1, b=-1, c=2 (coefficients of x2, x and 1 respectively)

substitute to get [(-1) +- sqrt(1-4(1)(2))]/2, or [-1 +- sqrt(-7)]/2

hence [-1 +- sqrt(7)i]/2

where I have used +-, it means the two answers are + the second term and - the second term

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