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I dont know how to solve this problem im very confused

label Algebra
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15y^2 = 3y

Nov 12th, 2014

15y^2-3y=0

3y(5y-1)=0

3 is not equal to 0 

Hence either y =0 or 5y=1

y=0 or y=1/5 =0.2

y=0 or y= 0.2

Nov 12th, 2014

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